find distance only section 6 Detailed Explanation And More Example
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DIRECTIONS:
- Point A is 8 m west of point B.
- Point E is 2 m east of point F.
- Point G is 3 m east of point H.
- Point E is 3 m north of point of point D.
- Point C is 9 m west of point D.
- Point G is 9 m north of point F.
- Point C is 6 m south of point B.
The following question based on direction & distance sense test topic of verbal reasoning
(a) $7√5 m$
(b) $6√6 m$
(c) $7√6 m$
(d) $6√5 m$
e) None of these
The correct answers to the above question in:
Answer: (d)
Vertical distance = GF – (CB – ED) = 9 – (6-3) = 6
Horizontal distance = AB + (CD – (HG + FE)) = 8 + (9 – (3+2) = 12
Required distance AH = $√ (6^2 + 12^2 ) = 6√5 m$
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Read more type 2 section 6 mcqs Based Verbal Reasoning Questions and Answers
Question : 1
A person starts from point G in east direction. Walks for 6 m, takes a right turn, now walks for 5 m. Now he takes a left turn, walks for 3 m, then after two consecutive right turns he reaches point E. Find the distance travelled by him to reach point E.
a) 25 m
b) 23 m
c) 27 m
d) 24 m
e) 28 m
Answer »Answer: (a)
6 + 5+ 3 + (9-5) + (3+4) = 25 m
Question : 2
A cyclist goes 30 km to North and then turning to East he goes 40 km. Again he turns to his right and goes 20 km. After this he turns to his right and goes 40 km. How far is he from his starting point ?
a) 10 km
b) 40 km
c) 20 km
d) 25 km
Answer »Answer: (a)
Question : 3
Deepak starts walking straight towards east. After walking 75 metres, he turns to the left and walks 25 metres straight. Again he turns to the left, walks a distance of 40 metres straight, again he turns to the left and walks a distance of 25 metres. How far is he from the starting point ?
a) 115 metres
b) 50 metres
c) 25 metres
d) 140 metres
e) None of these
Answer »Answer: (e)
The movements of Deepak are as shown in Figure.
Claerly, EB = DC = 40m.
∴ Deepak's distance from the starting point A
= (AB - EB) = (75 - 40)
= 35 m.
DIRECTIONS:
- Point B is 9 km east of point A.
- Point T is 6 km south of point B.
- Point S is 4 km west of point T.
- Point T is 8 km west of point G.
Question : 4
A person is standing on midpoint of line TG. Find his shortest distance from point B?
a) $5√14 km$
b) $6√3 km$
c) $3√15 km$
d) $2√13 km$
e) None of these
Answer »Answer: (d)
Let that point be Y. So Midpoint of TG means TY = $8/2$ = 4 km
So BY = $√(BT^2 + TY^2 ) = √ (6^2 + 4^2 ) = 2√13 km$
Question : 5
A person starts from point S, walks 3 km towards south and reaches point D. Next he takes two right turns and reaches point A. How much distance has he travelled?
a) 20 km
b) 17 km
c) 18 km
d) 14 km
e) 11 km
Answer »Answer: (c)
Let after first right turn he is at point K. Since after turn from K he reaches at point A so point K is in south of point A.
So he has travelled SD + DK + KA = 3 + (9-4) + (3+6) = 17 km
GET direction & distance sense test PRACTICE TEST EXERCISES
find directions only
find distance only
find both direction & distance
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find distance only section 2
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find distance only section 5
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find both direction & distance section 2
find both direction & distance section 3
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