find distance only section 4 Detailed Explanation And More Example

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The following question based on direction & distance sense test topic of verbal reasoning

Questions : Dheepthi started from point A in south direction. After walking for 4 m she turned to her right and walked 5 m. Now she turned to her left and walked 3 m after which she turned to her right. Now she walked 4 m and turned to her right again and walked 15 m. Now finally she turned to her right and after walking for 7 m, she stopped at point B. What is the distance AB?

(a) 34 m

(b) $3√17 m$

(c) $2√34 m$

(d) $2√17 m$

e) None of these

The correct answers to the above question in:

Answer: (d)

X = $√68= 2√17$

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Read more type 2 section 4 mcqs Based Verbal Reasoning Questions and Answers

Question : 1

A postman was returning to the post office which was in front of him to the south. When the post office is 80m away from him, he turned to the right and walks 50m to deliver the last letter. He continues walks in the same direction for 20 meter and then took a left turn and walks 80 meter. How many meters was he away from the post office

a) 40

b) 60

c) 30

d) 70

e) None of these

Answer: (d)

Question : 2

A man walks 30 metres towards South. Then, turning to his right, he walks 30 metres. Then, turning to his left, he walks 20 metres. Again, he turns to his left and walks 30 metres. How far is he from his initial position?

a) 30 metres

b) None of these

c) 20 metres

d) 60 metres

Answer: (b)

direction-and-distance

The movements of the man are as shown in figure.

So, Man’s distance from initial position A = AE

AE = (AB + BE) = (AB + CD) = (30 + 20) m = 50 m.

Question : 3

A person starts from point A, walks 10 m in south direction. Now he takes a left turn and walks 8m before turning left again. Next he walks 16 m and takes a right turn. Now he walks 4 m and takes a right turn again. He stops after walking 10 m. Find his distance from point A.

a) $3√10 km$

b) $4√10 km$

c) 20 km

d) $4√5 km$

e) 10 km

Answer: (b)

Required distance = $√((8+4)^2 + 4^2 ) = 4√10 km$

DIRECTIONS:
  1. Point D is 2 km to the north of point C.
  2. Point G is 8 km to the north of point H.
  3. Point A is 15 km to the south of point B.
  4. Point C is 8 km to the east of point B.
  5. Point E is 10 km to the north of point F which is 4 km to the west of point G.
  6. Point D is 4 km to the west of point E.

Question : 4

If a person starts from point H and reaches point S which is south of point C, then find distance CS + HS – EF

a) 13 km

b) 15 km

c) 12 km

d) 14 km

e) None of these

Answer: (d)

Point S is south of point C,

So CS = 8+8 = 16 km, HS = 4+4 = 8 km and EF is 10 km

So required answer = 16 +8 – 10 = 14 km

Question : 5

If a person after taking 2 turns reaches to point B from point F via point A, then what is the distance that he covered?

a) 34 km

b) 30 km

c) 32 km

d) 35 km

e) 36 km

Answer: (a)

Question : 6

Find shortest distance BH.

a) 32 km

b) 15 km

c) $16√4 km$

d) $16√2 km$

e) None of these

Answer: (d)

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