find both direction & distance Detailed Explanation And More Example
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The following question based on direction & distance sense test topic of verbal reasoning
(a) 3 km towards North
(b) 7 km towards East
(c) 6 km towards South
(d) 6 km towards West
e) 5 km towards North
The correct answers to the above question in:
Answer: (e)
According to the question, the direction diagram will be as follows.
Now, BC = DE = 5 km, CD = BE = 8 km AB = 2 km, EF = 1 km
Therefore, Required distance, AF = BE - (AB + EF) = 8 - (2 + 1) = 8 - 3 = 5 km.
From the direction diagram, it is clear that the bus is present finally in the South direction of school.
So, the driver needs to drive 5 km towards North direction to reach the school.
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Read more finding both direction distance test Based Verbal Reasoning Questions and Answers
Question : 1
Rajnikanth left his home foe office in car. He drove 15 km straight towards North and then turned Eastwards and covered 8 km. He, then turned to left and covered 1 km. He again turned left and drove for 20 km and reached office. How far and in what direction in his office from the home?
a) 21 km, West
b) 15 km, North - East
c) 20 km, North - West
d) 26 km, North - West
Answer »Answer: (c)
According to the question, the direction diagram will be as follows.
Now, AB = 15 km, CD = BF = 1 km
AF = AB + BF = 15 + 1 = 16 km
DE = 20 km DF = BC = 8 km
EF = DE - DF = 20 - 8 = 12 km
Therefore, Required distance, AE = $√{(AF)^2 + (EF)^2}$
= $√{(16)^2 + (12)^2}$
= $√{(256 + 144)}$ = √400 = 20 km
So, his office is 20 km North - West.
Question : 2
In an exercise, Krishnan walked 25 m towards South and then he turned to his left and moved for 20 m. He again turned to his left and walked 25 m. Thereafter, he turned to his right and walked 15 m. What is the distance and direction of his present location with reference to the starting point?
a) 74 m, North - East
b) 60 m, North
c) 35 m, East
d) 40 m, South - East
Answer »Answer: (c)
According to the question, the direction diagram will be as follows.
Now, AB = CD = 25 km, BC = AD = 20 m, DE = 15 m
Therefore, Required distance, AE = AD + DE AE = (20 + 15) = 35 m
Also, E is to the East of A.
Question : 3
Sharada started to move in the direction of South. After moving 15 m, she turned to her left twice and moved 15 m each time. Now, how far is she and in which direction from her starting point?
a) 20 m, west
b) 15 m, East
c) 15 m, South
d) 30 m, East
Answer »Answer: (b)
Let Sharada starts from point A and passing through B and C, she reaches D.
Clearly, she is in East and at a distance of 15 m from her original position.
Question : 4
Starting from a point, raju walked 12 ft North, he turned right and walked 10 ft, he again turned right and walked 12 ft, then the turned left and walked 5 ft. How far is he now and in which direction from the starting point?
a) 27 ft towards East
b) 5 ft towards East
c) 10 ft towards West
d) 15 ft towards East
e) 35 ft towards North
Answer »Answer: (d)
According to the questions, the direction diagram is as follows.
AB = CD = 12 ft
BC = AD = 10 ft
DE = 5 ft
Therefore, Required distance, AE = AD + DE = 10 + 5 = 15 ft
Hence at finishing point E, Raju is 15 ft East from starting point A.
Question : 5
Pankaj travels 10 m in North direction, he turns right and travels 20 m. Again he turns towards right and travels 25 m. Then, he turns towards left and travels 15 m. In which direction and how far is Pankaj from his original position?
a) 35 m, East
b) 10 m, West
c) 25 m, East
d) 55 m, West
e) None of these
Answer »Answer: (e)
According to the question, the direction diagram will be as follows.
A = Starting point, E = Finishing point DE = 15 m,
BC = FD = 20 m FE = FD + DE = 20 + 15 = 35 m
AF = BF - AB = 25 - 10 = 15 m
Therefore, Required distance, AE = $√{(AF)^2 + (FE)^2}$
= $√((15)^2 + (35)^2)$
= $√{(225 + 1225)}$
= $√1450$
and the direction is South-East
Question : 6
Sanjay's school is 10 $√2$ km in North - West direction from his house. The officee of his father is 10 km in South direction from the school. The multiplex hall is 10 km towards East from the school. How far and in which direction is the multiplex hall from the office of his father?
a) $10√2$ km, north - East
b) 20 km, North - East
c) 10 km, South - East
d) $20√2$ km, north - East
e) Cannot be determined
Answer »Answer: (a)
According to the question, the direction diagram will be as follows.
As in a square, diagonals are equal. Therefore, SH = OM = 10√2 km
Therefore, Required distance, OM = Distance between office and multiplex = 10√2 km
Also, it is clear from diagram that multiplex (M) is to the North - East of O (office)
So, the multiplex is $10√2$ km North - East from office.
GET direction & distance sense test PRACTICE TEST EXERCISES
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