type 1 angle between the hands of clock Detailed Explanation And More Example

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The following question based on clocks topic of verbal reasoning

Questions : Match List I with List II and select the correct answer using the codes given below the lists:
List I (Time) List II (Angle between hour hand and minute hand of a clock)
A. 1:10 PM 20°
B. 2:15 PM 22$1/2$°
C. 8:40 PM  24°
  25°
  30°

(a) A-4, B-2, C-1

(b) A-4, B-3, C-2

(c) A-5, B-2, C-1

(d) A-4, B-3, C-2

The correct answers to the above question in:

Answer: (a)

(A) Angle traced by hour hand in$ 7/6 hrs = (360/12 × 7/6)^o = 35°$

Angle traced by minute hand in $10 min = (360/60 × 10)^o = 60°$

∴ Required angle = (60° - 35°) = 25°

(B) Angle traced by hour hand in $9/4 hrs = (360/12 × 9/4)^o = 67 1°/2$

Angle traced by minute hand in $15 min = (360/60 × 15)^o = 90°$

∴ Required angle = $(90° - 67 1°/2) = 22 1°/2$

(C) Angle traced by hour hand in $26/3 hrs = (360/12 × 26/3)^o = 260°$

Angle traced by minute hand in $40 min = (360/60 × 40)^o$ = 240°

∴ Required angle = (260° - 240°) = 20°

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Read more find angle between hands clock Based Verbal Reasoning Questions and Answers

Question : 1

An accurate clock shows 8O' clock in the morning. Through how many degrees will the hour hand rotate when the clock shows 2O, clock in the afternoon?

a) 144°

b) 150°

c) 168°

d) 180°

Answer: (d)

Angle traced by the hour hand in $6 hours = (360/12 × 6)^o$ = 180°

Question : 2

The angle between the minute hand and the hour hand of a clock when the time is 4:20, is

a) 0°

b) 10°

c) 5°

d) 20°

Answer: (b)

Angle traced by hour hand in $13/3 hrs = (360/12 × 13/3)^o= 130°$

Angle traced by min. hand in $20 min = (360/60 × 20)^o = 120°$

∴ Required angle = (130° - 120°) = 10°

Question : 3

What will be the angle between the hands of clock at 9 : 30?

a) 75°

b) 90°

c) 105°

d) 120°

Answer: (c)

∴ Angle traced by hour hand per minute = $(1/2)^o$

∴ Angle traced by hour hand in 9 h 30 min

= [(9 × 60) + 30] × $1°/2$ = 570 × $1°/2$ = 285°

∴ angle traced by minute hand per minute = 6°

∴ angle traced by minute hand in 30 min = 30 × 6° = 180°

∴ required angle = (285° - 180°) = 105°

Question : 4

A clock gains 5 minutes in one hour. Therefore, the angle traversed by the minute hand in 1 hour is

a) 360°

b) 390°

c) 390.5°

d) None of these

Answer: (b)

Clearly, the minute hand traverses 65 minutes in 1 hour.

∴ Required angle = $(360/60 × 65)^o = 360°$ 

Question : 5

At what angle the hands of a clock are inclined at 15 minutes past 5?

a) $\text"58"1°/2$

b) 64°

c) $\text"67"1°/2$

d) $\text"72"1°/2$

Answer: (c)

Angle traced by hour hand in 21/4 hrs =$ (360/12 × 21/4)^o = 157 1°/2$

Angle traced by min. Hand in 15 min = $(360/12 × 15)^o = 90°$

∴ Required angle = $(157 1°/2) - 90° = 67 1°/2$.

Question : 6

What will be the angle between the hands of clock at 8 : 30?

a) 15°

b) 30°

c) 45°

d) 75°

Answer: (d)

∴ Angle traced by hour hand per minute = $(1/2)^o$

∴ Angled traced by hour hand in 8 h 30 min =$[{(8 × 60) + 30}x1/2]^o$

= $[{480 + 30} ×1/2]° = 510 × (1/2)^o = 255°$

Then,  Angle traced by minute hand per minute = 6°

∴ Angle traced by minute hand in 30 min = 30 × 6° = 180°

Hence, Required angle = (255° - 180°) = 75°

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