type 1 angle between the hands of clock Detailed Explanation And More Example

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The following question based on clocks topic of verbal reasoning

Questions : At what angle the hands of a clock are inclined at 15 minutes past 5?

(a) $\text"58"1°/2$

(b) 64°

(c) $\text"67"1°/2$

(d) $\text"72"1°/2$

The correct answers to the above question in:

Answer: (c)

Angle traced by hour hand in 21/4 hrs =$ (360/12 × 21/4)^o = 157 1°/2$

Angle traced by min. Hand in 15 min = $(360/12 × 15)^o = 90°$

∴ Required angle = $(157 1°/2) - 90° = 67 1°/2$.

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Read more find angle between hands clock Based Verbal Reasoning Questions and Answers

Question : 1

A clock gains 5 minutes in one hour. Therefore, the angle traversed by the minute hand in 1 hour is

a) 360°

b) 390°

c) 390.5°

d) None of these

Answer: (b)

Clearly, the minute hand traverses 65 minutes in 1 hour.

∴ Required angle = $(360/60 × 65)^o = 360°$ 

Question : 2

Match List I with List II and select the correct answer using the codes given below the lists:

List I (Time) List II (Angle between hour hand and minute hand of a clock)
A. 1:10 PM 20°
B. 2:15 PM 22$1/2$°
C. 8:40 PM  24°
  25°
  30°

a) A-4, B-2, C-1

b) A-4, B-3, C-2

c) A-5, B-2, C-1

d) A-4, B-3, C-2

Answer: (a)

(A) Angle traced by hour hand in$ 7/6 hrs = (360/12 × 7/6)^o = 35°$

Angle traced by minute hand in $10 min = (360/60 × 10)^o = 60°$

∴ Required angle = (60° - 35°) = 25°

(B) Angle traced by hour hand in $9/4 hrs = (360/12 × 9/4)^o = 67 1°/2$

Angle traced by minute hand in $15 min = (360/60 × 15)^o = 90°$

∴ Required angle = $(90° - 67 1°/2) = 22 1°/2$

(C) Angle traced by hour hand in $26/3 hrs = (360/12 × 26/3)^o = 260°$

Angle traced by minute hand in $40 min = (360/60 × 40)^o$ = 240°

∴ Required angle = (260° - 240°) = 20°

Question : 3

An accurate clock shows 8O' clock in the morning. Through how many degrees will the hour hand rotate when the clock shows 2O, clock in the afternoon?

a) 144°

b) 150°

c) 168°

d) 180°

Answer: (d)

Angle traced by the hour hand in $6 hours = (360/12 × 6)^o$ = 180°

Question : 4

What will be the angle between the hands of clock at 8 : 30?

a) 15°

b) 30°

c) 45°

d) 75°

Answer: (d)

∴ Angle traced by hour hand per minute = $(1/2)^o$

∴ Angled traced by hour hand in 8 h 30 min =$[{(8 × 60) + 30}x1/2]^o$

= $[{480 + 30} ×1/2]° = 510 × (1/2)^o = 255°$

Then,  Angle traced by minute hand per minute = 6°

∴ Angle traced by minute hand in 30 min = 30 × 6° = 180°

Hence, Required angle = (255° - 180°) = 75°

Question : 5

What angle will be traced by the hands of a clock at 7 : 35?

a) $7 1°/2$

b) $17 1°/2$

c) $27 1°/2$

d) $37 1°/2$

Answer: (b)

Angle traced by hour hand per minute = $(1/2)^o$

∴ Angle traced by hour hand in 7 h 35 min = [(7 × 60) + 35] × $1°/2$

= (420 + 35) × 1°/2 = 455 × $1°/2$ = 227 $1°/2$

∴ angle traced by minute hand per minute = 6°

Angle traced by minute hand in 35 min = 35 × 6° = 210°

∴ required angle = 227 1°/2 - 201° = 17$1°/2$

Question : 6

Find the angle traced by hour hand of a correct clock between 8 O' clock and 2O' clock.

a) 180°

b) 168°

c) 150°

d) 144°

Answer: (a)

∴ Angle traced by hour hand per minute = $(1/2)^o$

∴ Angle traced by hour hand in 1 h = 1°/2 × 60 = 30°

Time period between 8 O' clock to 2 O' clock = 6h

∴ angle traced by hour hand in 6h = 30° × 6 = 180°

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