type 3 faulty clock Detailed Explanation And More Example
MOST IMPORTANT verbal reasoning - 5 EXERCISES
The following question based on clocks topic of verbal reasoning
(a) 2 min 52 s past 10
(b) 2 min 54 s past 10
(c) 2 min 50 s past 10
(d) 2 min 48 s past 20
The correct answers to the above question in:
Answer: (a)
Total time from 3 O' clock Sunday afternoon to 10 O' clock Tuesdy morning = 43 h
Total increased time = 12/3 × 43 = 172s = 2 min 52s
Therefore, Time at 10 O' clock Tuesday morning = 2 min 52 s past 10
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Read more faulty clocks Based Verbal Reasoning Questions and Answers
Question : 1
A watch, which gains uniformly is 2 min slow at noon on Monday and is 4 min, 48s fast at 2 pm on the following Monday. At what time it was correct?
a) 2 pm on Tuesday
b) 2 pm on Wednesday
c) 3 pm on Thursday
d) 1 pm on Friday
e) None of these
Answer »Answer: (b)
Time from Monday noon (12 pm) to 2 pm the following Monday = 7 days 2 h = 170 h
Now, the watch gains (2 + 4 4/5) min from Monday (12 pm) to 2 pm,
the following Monday. In other words, the watch gains 34/5 min in 170 h.
Therefore, it will gain 2 min in (170 × 5/34 × 2) = 50 h = 2 days 2 h
Therefore, the watch is correct after 2 days 2 h from Monday noon or at 2 pm Wednesday.
Question : 2
A clock is set right at 5 am. The clock loses 16 min in 24 h. What will be the right time when the clock indicates 10 pm on the 3rd day?
a) 11 : 15 pm
b) 11 pm
c) 12 pm
d) 12 : 30 pm
Answer »Answer: (b)
Time from 5 am of a particular day to 10 pm on the 3rd day is 89 h.
Now, the clock loses 16 min in 24 h or in other words,
we can say that 23 h 44 min of this clock is equal to 24 h of the correct clock.
$(23 + 44/60) = 356/15$ h of this clock = 24h of the correct clock
Therefore, 89 h of this clock = $(24 × 15 / 356 × 89) h$
the correct clock = 90 h of the correct clock or 89 h of this clock = 90 h of the correct clock.
Therefore, it is clear that in 90 h this clock loses 1 h and hence, the correct time is 11 pm when this clock shows 10 pm.
Question : 3
A clock, which loses uniformly, is 15 min fast at 9 am on 3rd of the December and is 25 min less than the correct time at 3 pm on 6th of the same month. At what time it was correct?
a) 2 : 15 am on 3rd
b) 2 : 15pm on 4th
c) 2 : 15 pm on 3rd
d) 2 : 15 am on 4th
Answer »Answer: (c)
Time of the last train leaving the station = (18 : 00 - 2 : 30)h = 15 : 30h
But this happens 40 min before the announcement is made.
Hence, Time of making announcement = (15 : 30 + 0 : 40) = 16 : 10h
GET clocks PRACTICE TEST EXERCISES
type 1 angle between the hands of clock
type 2 position of hands of the clock
type 3 faulty clock
type 4 time gained or lost by clock
type 5 comparing clocks
clocks Shortcuts and Techniques with Examples
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