type 10 conditional coding & decoding Detailed Explanation And More Example

Answer: (e)

When no condition is applied, coding is done as follows. P → * Q → 4 I → 9 M → % H → © Z © 1

But here the first letter is a consonant and the third letter is a vowel, therefore condition (i) is applied.

As condition (i) is applied here, the codes for first and third letters are to be interchanged.

P → 9 Q → 4 I → * M → % H → © Z → 1

Hence, code for PQIMHZ ⇒ 94*%©1.

Answer: (b)

When no condition is applied, the coding is done as follows.

F → 5 W → d Z → 1 E → # R → 7 A → $

But here the second and third letters are consonants, therefore condition (iii) is applied here.

As condition (iii) is applied here, both the second and third letters are to be coded as the code for the third letter.

F → 5 W → 1 Z → 1 E → # R → 7 A → $

Hence, code for FWZERA ⇒ 511#7$.

Answer: (e)

Here, none of the conditions is applied,

so the coding is done as follows.

N → 3, O → @, B → 2, O → @, Q → 4, E → #.

Hence, code for NABAQE ⇒3@2@4#.

Answer: (d)

Here, none of the conditions is applied.

So the coding is done as follows. A → 4 J → 9 B → * M → # F → 8 U → ©

Hence, code for AJBMFU ⇒ 49*#8©.

Answer: (a)

When the condition is not applied, the coding is done as follows.

T → 3 H → $ A → 4 F → 8 I → @ Q → 1

But here both the first and the last latter are consonants, therefore condition (iii) is applied here.

As condition (iii) as applied here, the codes for the first and the last letters are interchanged.

T → 1 H → $ A → 4 F → 8 I → @ Q → 3

Hence, code for THAFIQ ⇒ 1$48@3.

Answer: (e)

Here, none of the conditions is applied,

so the coding is done as follows. M → # B → * U → © V → 7 W → 5 E → 2

Hence, code for MBUVWE ⇒ #*©752