ratio and proportion Model Questions & Answers, Practice Test for ssc mts tier 1 2024

Answer: (a)

Let the weight of the three pieces be x, 3x and 6x and value (V) ∝ square of W

V ∝ $W^2$ ⇒ $V/{W^2}$ = constant = ${30000}/{(10x)^2}$

∴ loss due to breakage

= ${30000(10x)^2- (x)^2 + (6x)^2}/{(10x)^2} = {3000x54x^2}/{100x^2}$ = 16200

Answer: (c)

A : B = 2 : 5 → × 3

B : C = 3 : 4 → × 5

Now, A : B = 6 : 15

B : C = 15 : 20

So A : B : C = 6 : 15 : 20

Answer: (a)

Using the options and the first given condition, we get x – 5 = 3(y – 5)

Using the option (a),

x - 5 = 3(y - 5)⇒30 - 5 = 3(y - 5)

⇒25 = 3y - 15⇒40

which gives value of y as a fraction.

Using the option (b),

x - 5 = 3(y - 5)⇒32 - 5 = 3(y - 5)

⇒27 = 3(y – 5)⇒9 = y – 5⇒y = 14

Using the option (c),

x - 5 = 3(y - 5)⇒36 - 5 = 3(y - 5)

⇒31 = 3y – 15⇒46 = 3y

which gives value of y as a fraction.

Using the option (d),

x - 5 = 3(y - 5)⇒40 - 5 = 3(y -5)

⇒35 = 3y – 15⇒50 = 3y

which also gives the value of y as a fraction.

Since only option (b) gives the final value of y as an integer, therefore option (b) is the correct answer

Answer: (b)

Let 40% of A = $2/3$ B . Then, ${{40A}/{100}} = {{2B}/{3}}⇒{{2A}/{5}}={{2B}/3}$

⇒$A/B = ({2/3} × {5/2}) = 5/3$

∴ A : B = 5 : 3

Answer: (c)

Let annual income of one person = 9x

Let annual income of second person = 7x

Let Expenses of Ist person = 4y

Let Expenses of 2nd person = 3y

Saving of Ist person = 2000

Saving of 2nd person = 2000

According to condition,

9x – 4y = 2000

7x – 3y = 2000

On solving, we get

x = 2000

Annual income of 1st person = 9 × 2000 = 18000

Annual income of 2nd person = 7 × 2000 = 14000

Difference between their incomes = Rs. 4000

∴ Option (a) is correct.