time and distance Model Questions & Answers, Practice Test for ssc mts tier 1 2024

Answer: (a)

Let us assume that speed of X = 5m/s

∴ speed of Y = 6m/s

Time taken by Y to cover 1.2 km race

$t_Y = {1200}/6$ = 200sec

Time taken by X to cover 1.2 km race

$t_X = {1200 – 70}/5 = {1130}/5$ = 226sec

So Y wins the race by 26 sec.

Distance travelled by X in

26 sec = 26 × 5 = 130 m

Answer: (d)

Speed of bike = 25 – 50 km/h

Consumption of petrol at 25-50 hm/hr = 20 ml/km

and consumes petrol = 40 ml/km at other speed

Given Distance

50km → 10 km + 30 km + 10 km

Speed → 40 km/hr 60 km/hr 30 km/hr

Petrol consumed = (10 + 10) × 20 ml + 30 × 40 ml

= 400 ml + 1200 ml

= 1600 ml

= ${1600}/{100}$ L = 1.6L

∴ Option (d) is correct.

Answer: (a)

Total distance covered = 300 + 500 = 800 km.

Total time taken to cover 800 km

= $300/45+500/60=20/3+25/3=45/3$=15hr.

∴ Average speed = $800/15=160/3=53{1/3}$ kmph

Answer: (d)

When speed ratio is $S_1 : S_2 : S_3 : S_4$

than time ratio will be $1/{S_1} : 1/{S_2} : 1/{S_3} : 1/{S_4}$ ...

i.e. time ratio $1/2 : 1/3 : 1/4$

⇒6 : 4 : 3

Answer: (a)

Radius of wheels = ${80}/2$ cm = 40 cm

Wheel covers in 1 revolution = 2πr = 2 × ${22}/7$ × 40

Speed of wheel = 66 km/hr or

${66 × 1000 × 100 cm}/{60 min}$

Distance covered in 10 minutes

= ${66 × 1000 × 100 × 10}/{60}$

No. of revolution = ${66 × 1000 × 100 × 10}/{60 × 2 × 22 × 40}$ × 7 = 4375