Mensuration Model Questions & Answers, Practice Test for ssc mts tier 1 2024

Answer: (a)

At sometimes, the container was full.

At 25 minutes, it was holy full.

At 20 minutes, it was the fourth full.

So, option (c) is correct.

Answer: (d)

Perimeter of the circle = 2 π r = 2(18 + 26)

⇒2 × ${22}/7$ × r = 88⇒r = 14

∴ Area of the circle

=π $r^2 = {22}/{7} × 14 × 14 = 616 cm^2$.

Answer: (a)

Area of tank, BCDE = 10 × 7.5 = 75 $m^2$

Area of remaining field ABEDFGA

= 125 × 15 – 75 = 1800 sq m

Volume of Earth dug = 10 ×7.5 × 6 = 450 cu m

By given condition, 1800 × h = 450

⇒ h = $1/4 m = 1/4 × 100$ cm = 25 cm

Answer: (a)

edge of cube = 2a

radius of cone = ${2a}/2$ = a

hight of cone = 2a

Volume of cone = $1/3 π r^2 h = 1/3 × π × a^2 × 2a$

= ${2a^3 π}/3 = {2πa^3}/3$

Answer: (b)

As we know that, if the length of square and rhombus are same, then the area should be same

∴ x : y = 1 : 1