mensuration Model Questions & Answers, Practice Test for ssc mts tier 1 2024
ssc mts tier 1 2024 SYLLABUS WISE SUBJECTS MCQs
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Lcm & Hcf
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Mensuration
A bicycle is running straight towards North. What is the locus of the centre of the front wheel of the bicycle whose diameter is d?
Answer: (c)
The locus of the centre of the front wheel of the bicycle is a line parallel to the path of the wheel of the bicycle at a height d/2 cm.
Two circles with centres A and B touch each other internally, as shown in the figure given above. Their radii are 5 and 3 units, respectively. Perpendicular bisector of AB meets the bigger circle in P and Q. What is the length of PQ?
Answer: (a)
AM = 5 cm
BM = 3 cm
AB = 5 – 3 = 2 cm
PQ Bisect AB
∴ OA = OB = 1 cm
In ΔAOP
∴ OP = $√{AP^2 - OA^2} = √{5^2 - 1^2}$
= $√{25 - 1} ∼ = √{24} = 2 √6$
∴ PQ = 2 × OP = 2 × 2 $√6 = 4 √6$ cm
If the heights and the areas of the base of a right circular cone and a pyramid with square base are the same, then they have
Answer: (a)
Volume of cone and pyramid = $1/3$ × Base area × Height
Since, volume of cone and pyramid are same but their surface area are not same because of their slant height.
A large solid metallic cylinder whose radius and height are equal to each other is to be melted and 48 identical solid balls are to be recast from the liquid metal, so formed. What is the ratio of the radius of a ball to the radius of the cylinder?
Answer: (d)
Volume of cylinder = π $r_1^2$h
Volume of ball = $4/3πr_2^3$
Number of balls = 48
∴ Number of balls = ${\text"Volume of cylinder"}/{\text"Volume of balls"} = {πr_1^2h}/{4/3 πr_2^3}$
⇒ ${πr_1^2 h}/{4/3 πr_2^3} = 48 ⇒ {πr_1^3}/{4/3 πr_2^3}$ = 48
(∵ $r_1$ = h)
⇒ $3/4(r_1/r_2)^3 = 48 ⇒ (r_1/r_2)^3 = {48 × 4}/3$
⇒ $r_1/r_2 = (16 × 4)^{1/3} ⇒ r_2/r_1 = 1/4$
Thus, the ratio of radius of ball to cylinder is 1 : 4.
Two circles of radii 20 cm and 16 cm intersect and the length of common chord is 24 cm. If d is the distance between their centres, then which one of the following is correct ?[2020-I]
Answer: (c)
AX = $√{400 –144}$ = 16
BX = $√{256 – 144} = √{112}$ = 10.6
AB = (16 + 10.6) ≈ 26.6
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