lcm and hcf Model Questions & Answers, Practice Test for ssc mts tier 1 2024

Answer: (a)

24 = 12 × 2,

36 = 12 × 3,

48 = 12 × 4,

and 72 = 12 × 6

∴ HCF (24, 36, 48, 72) = 12

Total pieces = 2 + 3 + 4 + 6 = 15

Answer: (d)

LCM of 6, 8, 12 is 24

Number is when divided by 6, 8 and 12 leaves 5, 6 and

11 as remainders, as 6 – 5 = 1, 8 – 7 = 1, 12 – 11 = 1

So (24 k – 1) will be divisible by 13.

⇒${24k - 1}/{13}$, is divisible for $k_{min}$ = 6

at k = 6

Number is = 24 k – 1

= 24 × 6 – 1 = 143

Sum of its digit = 1 + 4 + 3 = 8

So, option (d) is correct

Answer: (c)

Let numbers be 21x and 21y

According to the question

21x × 21y = 21 × 3003

x + y = ${21 × 3003}/{21 × 21}$ = 143

Possible pairs of values of x and y are (1, 143) and (11, 13)

Both numbers are greater than 21. Hence, (11, 13) is right pair of co-prime factors

Sum of numbers = 11 × 21 + 13 × 21 = 231 + 273 = 504

Answer: (a)

${11}/{14}$

Answer: (d)

${17}/6$ only fraction whose dinominator is not in form of $2^m 5^n$ when simplified