averages Model Questions & Answers, Practice Test for ssc mts paper 1

Answer: (b)

Put x = 10 in the given equations and find the average of the resultant values.

Answer: (c)

3rd Number = (5 × 213) – (2 × 233.5) – (2 × 271)

= 56

Answer: (b)

Let the ages of Abhay and his father 10 years ago be x and 5x years respectively. Then,

Abhay's age after 6 years

= (x + 10) + 6 = (x + 16) years.

Father's age after 6 years

= (5x + 10) + 6 = (5x + 16) years.

∴ (x + 16) = $3/7(5x + 16)$

⇔ 7 (x + 16) = 3 (5x + 16)

⇔ 7x + 112 = 15x + 48

⇔ 8x = 64 ⇔ x = 8.

Hence, Abhay's father's present age

= (5x + 10) = 50 years.

Answer: (a)

37a + 37b = 5661

or, 37(a + b) = 5661

or, a + b = $5661/37$ = 153

∴ Average = ${a + b}/2 = 153/2 = 76.5$

Answer: (c)

Let the consecutive even numbers are

2n, 2n + 2, 2n + 4 and 2n + 6

Average = ${2n + 2n + 2 + 2n + 4 + 2n + 6}/4$

8n + 12 = 4 × 9 ⇒ n = 3

Hence, the numbers are 6, 8, 10 and 12.

Largest among them is 12.