number system Model Questions & Answers, Practice Test for ssc mts paper 1 2023

Answer: (c)

Let the original number of persons be x.

Then, ${6500}/x = 6500/{x + 15} + 30$

or ${6500}/x = {6500 + 30x + 450}/{x + 15}$

or $x^2 + 15x - 3250 = 0$

or x = 50

Answer: (c)

Suppose the number is x.

$x × 1/5 × 3/4 × 2/3 = 15$

$x = 15 × 5/1 × 4/3 × 3/2 = 15 ⇒ x = 150$

30% of x = 150 × 3 = 45

Answer: (b)

Numbers from (0 – 999) divisible by 7,

$999/7 = 142{5}/7 ≈ 142$

Numbers from (0 – 999) divisible by 5,

$999/5 = 199{4}/5 ≈ 199$

There are few numbers which are divisible by both 5 and 7, i.e., by 35.

Numbers from (0 – 999) divisible by 35,

$199/35 = 28{19}/35 ≅ 28$

Numbers divisible by 5 or 7 = 142 + 199 – 28 = 313

Hence, total numbers between (0 – 999) not divisible by 5 or 7 = 999 – 313 = 686

Answer: (b)

Suppose each child got x sweets.

∴ 112 × x = (112 – 32) × (x + 6)

112 x = 80 × (x + 6)

112 x = 80x + 480

112 x – 80 x = 480

x = 15

Answer: (c)

45 = $3^2 × 5$.

Hence, we need to count the number of $3^2$ 's and 5's that can be made out of 123!.

Number of 3's = 41 + 13 + 4 + 1 = 59 →Number of $3^2$ 's = 29

Number of 5's = 24 + 4 = 28.

The required answer is the lower of the two (viz. 28 and 29).

Hence, option (a) 28 is correct.