number system Model Questions & Answers, Practice Test for ssc chsl tier 1 2023
ssc chsl tier 1 2023 SYLLABUS WISE SUBJECTS MCQs
Number System
Simplification
Powers Surds & Indices
Ratio Proportion & Partnership
Percentages
Profit & Loss
Time & Work
Time & Distance
Simple Interest & Compound Interest
Mensuration: Area & Volumes
A boy multiplied a certain number x by 13. He found that the resulting product consisted of all nines entirely. Find the smallest value of x.
Answer: (b)
By actual division, we find that 999999 is exactly divisible by 13.
The quotient 76923 is the required number.
A person has only Rs. 1 and Rs. 2 coins with her. If the total number of coins that she has is 50 and the amount of money with her is Rs. 75, then the number of Rs. 1 and Rs. 2 coins are, respectively
Answer: (d)
Let the no. of Rs. 1 coins = x
and the no. of Rs. 2 coins = y
According to the question:
x + y = 50 ... (i)
x.1 + 2. y = 75 ... (ii)
on solving (i) and (ii), we get
2y – y = 75 – 50 ⇒ y = 25
put value of y in equation (i), we get
x = 50 – y
= 50 – 25 = 25
Hence, number of Rs. 1 and Rs. 2 coins are 25 and 25 respectively
Consider the following statements for the sequence of numbers given below :
11, 111, 1111, 11111, ...
- Each number can be expressed in the form (4m + 3), where m is a natural number.
- Some numbers are squares.
Answer: (c)
11, 111, 1111, 11111, ...
1 Each number is divided by 4 then their remainder are always 3.
So, it can be written as = 4 m + 3
So statement is true.
2 No, this type of numbers are not squares.
So it is not true. Only 1 is true.
At a college football game, 4/5 of the seats in the lower deck of the stadium were sold. If 1/4 of all the seating in the stadium is located in the lower deck, and if 2/3 of all the seats in the stadium were sold, then what fraction of the unsold seats in the stadium was in the lower deck ?
Answer: (c)
Let total number of seats in the stadium be p; number of seats in the lower deck be x and number of seats in upper deck be y.
∴ p = x + y, x = p/4, y = 3p/4
Now in the lower deck, 4x/5 seats were sold and x/5 seats were unsold.
No. of total seats sold in the stadium = 2p/3.
No. of unsold seats in the lower deck = x/5 = p/20
No. of unsold seats in the stadium = p/3
∴ Required fraction = ${p/20}/{p/3} = 3/20$
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