time and work Model Questions & Answers, Practice Test for ssc cgl tier 1 2023
ssc cgl tier 1 2023 SYLLABUS WISE SUBJECTS MCQs
Number System
Ratio Proportion & Partnership
Averages
Percentages
Profit & Loss
Time & Work
Time & Distance
Simple Interest & Compound Interest
Mensuration: Area & Volumes
Algebraic Expressions
Linear Equations
Squareroots & Cuberoots
If I walk at 4 km/h, I miss the bus by 10 minutes. If I walk at 5 km/h, I reach 5 minutes before the arrival of the bus. How far I walk to reach the bus stand ?
Answer: (a)
d = product of speed $[{\text"difference of time"}/{\text"difference of speed"}]$
d = ${4 × 5}/{60}[{10 - (-5)}/{5 - 4}]$[Here, –ve sign indicates before the schedule time]
⇒ d = 5 km
Local trains leave from a station at an interval of 14 minutes at a speed of 36 km/h. A man moving in the same direction along the road meets the trains at an interval of 18 minutes. Find the speed of the man.
Answer: (a)
Let speed of man = S km/h. Then,
36 × ${14}/{60} = {18}/{60}$[36 - S]⇒36 - S = 28⇒S = 8 km/h.
A car covers 420 km with a constant speed. If its speed were 10 km/h more it would have taken one hour less to cover the distance. Find the speed of the car.
Answer: (a)
Let the speed of car = S km/h.
Also, let previous time = t hr. Then,
420 = St ... (i)
Also , 420 = (S + 10) (t – 1)
⇒420 = $(S + 10)({420}/S - 1)$ [By (i)]
⇒$S^2$ + 10S - 4200 = 0
⇒ (S + 70) (S – 60) = 0
⇒ S = 60 km/h
A person can walk a certain distance and drive back in six hours. He can also walk both ways in 10 hours. How much time will he take to drive both ways?
Answer: (a)
2-way walk = 10 hrs
∴ 1-way walk = 5 hrs
1-way walk + 1 way drive = 6 hrs
∴ 1 way drive = 6 – 5 = 1 hr
Hence, two way drive take 2 hrs.
One hundred men in 10 days do a third of a piece of work. The work is then required to be completed in another 13 days. On the next day (the eleventh day) 50 more men are employed, and on the day after that, another 50. How many men must be discharged at the end of the 18th day so that the rest of the men, working for the remaining time, will just complete the work ?
Answer: (b)
Suppose that X men must be discharged at the end of the 18th day.
100 × 10 + 150 × 1 + 200 × 7 + (200 – X) × 5 = 100 × 305X = 550⇒X = 110 men
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