time and distance Model Questions & Answers, Practice Test for ssc cgl tier 1 2023
ssc cgl tier 1 2023 SYLLABUS WISE SUBJECTS MCQs
Number System
Ratio Proportion & Partnership
Averages
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Profit & Loss
Time & Work
Time & Distance
Simple Interest & Compound Interest
Mensuration: Area & Volumes
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Linear Equations
Squareroots & Cuberoots
A man takes 6 hrs 30 min in walking to a certain place and riding back. He would have gained 2 hrs 10 min by riding both ways. How long would he take to walk both ways?
Answer: (a)
Walking + Riding = 6 hrs 30 min ……(1)
2 Riding = 6 hrs 30 min – 2 hrs 10 min
= 4 hrs 20 min ……(2)
Solving the above two relations (equations);
2 × (1) – (2) gives
2 walking = 13 hrs – 4 hrs 20 min = 8 hrs 40 minutes
My mother left for Nasik from Pune at 5.20 AM. She travelled at the speed of 50 km/hr for 2 hour 15 minutes. After that the speed was reduced to 60 km/hr. If the distance between two cities is 350 km, at what time did she reach Nasik?
Answer: (d)
In covering a certain distance, the speeds of A and B are in the ratio of 3 : 4. A takes 30 minutes more than B to reach the destination. The time taken by 'A' to reach the destination is
Answer: (a)
Let B takes x H
then A takes ${(x+1/2)}H$
∴ ${(x+1/2)}3=x × 4$
6×+3=8x
2x=3
x = $3/2$
∴ A takes=$3/2+1/2$
= 2 Hrs.
Excluding the stoppages, the speed of a bus is 64 km/hr and including the stoppages the speed of the bus is 48 km/hr. For how many minutes does the bus stop per hour?
Answer: (a)
Stoppage minutes per hour
= ${(64-48)×60}/64$ = 15 minutes.
A car travelling with $5/7$ of its actual speed covers 42 km in 1 hr 40 min 48 sec. The actual speed of car is
Answer: (b)
Let actual speed = x
∴ ${5/7}x×6048/3600=42$
$x={42×7×3600}/{5×6048}$
x = 35 km/h
ssc cgl tier 1 2023 IMPORTANT QUESTION AND ANSWERS
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