profit and loss Model Questions & Answers, Practice Test for ssc cgl tier 1 2023

Answer: (c)

The following alligation visualization would help us solve the problem:

= 4.1666 : 5.8333

= 25 : 35

= 5 : 7

Cost of cupboard = 5 × 18000/12 = 7500.

Answer: (b)

Let the CP be x

Loss = $1/16 × x = x/16$

SP = CP – Loss

150 = $x – x/16$

150 = ${15x}/16$ or

$x = {150 × 16}/15$ = 160.

Answer: (c)

Ist case :

S.P = ${100 + \text"Profit"%}/100$ × C.P.

S.P. = ${100 + 25/2 × C.P}/100$

S.P = $112.5/100$ CP ...(1)

IInd case :

S.P = ${100 + \text"Profit" %}/100$ × C.P.

(S.P + 10) = ${100 + 15}/100$ × C.P.

⇒ (S.P+10) = $115/100$ C.P ...(2)

Dividing equation (1) by (2)

$\text"S.P"/{\text"S.P" + 10} = 112.5/100 (C.P) × 100/{115(C.P)}$

S.P = $(112.5/115)$ (S.P + 10)

115 S.P = 112.5 SP + 1125

S.P = 450

∴ C.P = ${\text"S.P" × 100}/112.5 = {450 × 100}/112.5$ = 400

Answer: (a)

When $S_1 = S_2$, then

overall % gain or % loss

= $[100 - {2(100 + x_1)(100 - x_2)}/{(100 + x_1) + (100 - x_2)}]%$

= $(100 - {2(125)(80)}/{(125) + (80)})% = (100 - {2 × 125 × 80}/205)%$

= $100/41$ % gain (it is +ve)

Answer: (a)

Cost price = ${2817.50 × 100}/115$ = Rs. 2450