mensuration area volumes Model Questions & Answers, Practice Test for ssc cgl tier 1 2023

Answer: (b)

$D_S = 2R$

$D_S^2 = (2R)^2$

${\text"Area of circle"}/{\text"Area of square"} = {πR^2}/{1/2 D_S^2} = π/2 = {22}/{14} = {11}/7$

Answer: (c)

The diameter of Moon is approximately one-fourth of the diameter of Earth.

Let radius of Moon = r,

then radius of Earth = 4r

Required ratio =

${\text"Volume of Moon"}/{\text"Volume of Earth"} = {4/3 π r^3}/{4/3 π (4r)^3} = r^3/{64r^3} = 1/{64}$ = 1 : 64

Answer:(d)

The distance between vertices B and C is 1 cm.

The distance between A and B is $√{1^2 + 2^2} = √2$ cm

The distance between diagonal B and D is

$√{1^2 + 1^2 + 1^2} = √3$ cm

Answer: (c)

∵ Circumference of circular path = 2π × 50 m = 10000π cm

and circumference of wheel = 2π × 50 = 100π cm

∴ Distance covered in 60 min = 10000π cm

Distance covered in 1 min = ${10000}/{60}$ π

Distance covered in 15 min

= ${10000}/{60}$ π × 15 = 2500π cm

∴ Number of revolutions = ${2500π}/{100π}$ = 25

Answer: (d)

Internal diameter of the tube = 6 cm

∴ Internal radius (r) = 3 cm

Height of the tube (h) = 10 cm

Thickness of the metal = 1 cm

∴ Outer radius (R) = Thickness of the metal + Internal radius = 1 + 3 = 4 cm

∴ Outer curved surface area

= 2πrh + 2π $(R^2 - r^2)$

= 2π(3)(10) + 2π (16 - 9)

= 60π + 14π = 74 π sq cm