profit and loss Model Questions & Answers, Practice Test for ibps so prelims
'A' got 30% concession on the label price of an article sold for Rs.8750 with 25% profit on the price he bought. The label price was
Answer: (b)
CP = SP × $100/{100 + \text"P"%}$
= 8750 × $100/125$ = 7000
MP = CP × $100/{100 - 0%}$
= 7000 × $100/{100 - 30%} = 7000 × 100/70$ = 10,000
An article was purchased for 78,350/–. Its price was marked up by 30%. It was sold at a discount of 20% on the marked up price. What was the profit percent on the cost price ?
Answer: (c)
MP = 78,350 × 130% = 101855
SP = 101855 × 80% = 81484
Profit = 81484 – 78350 = 3134
Profit % = $3134/78350 × 100$ = 4%
A bought an article, paying 5% less than the original price. A sold it with 20% profit on the price he had paid. What percent of profit did A earn on the original price ?
Answer: (c)
Required % earned by A
=$(100 × (100 - 5)/100 × (100 + 20)/100 - 100)$ %
= $(100 × 95/100 × 120/100 - 100)$ %
= (114 –100)% = 14%
A man purchased an article at $3/4$ th of the list price and sold at half more than the list price. What was his gain per cent ?
Answer: (d)
Let the listed price be = Rs. 100
Then, CP = $3/4 × 100$ = Rs. 75
and SP = $3/2 × 100$ = Rs. 150
% profit = ${150 - 75}/75 × 100$ = 100%
The printed price of a book is Rs.320. A retailer pay Rs.244.80 for it. He gets successive discounts of 10% and an another rate. His second rate is :
Answer: (b)
320$(1 - 10/100)(1 - \text"D"_2/100)$ = 244.80
320 × $90/100 × (1 - \text"D"_2/100)$ = 244.80
288 × $(1 - \text"D"_2/100)$ = 244.80
288 - ${288\text"D"_2}/100$ = 244.80
${- 288\text"D"_2}/100$ = 244.80 - 288
${288\text"D"_2}/100$ = 43.2
$\text"D"_2 = {43.2 × 100}/288$ = 15%
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