profit and loss Model Questions & Answers, Practice Test for ibps so prelims

Answer: (c)

The cost price of an article

= ${996 + 894}/2 = 1890/2$ = Rs. 945

Answer: (c)

SP = CP × $(100 + \text"Profit"%)/100$

= 1850 × $130/100$ = 2405

Answer: (d)

Suppose the S.P. per metre = Rs. 1

Then, S.P. of 33 metres = Rs. 33

Profit = Rs. 11

∴ C.P. of 33 metres = 33 – 11 = Rs. 22

∴ % Profit = $11/22 × 100$ = 50%

Answer: (c)

Let original price of sewing machine be Rs. x

Retailer bought it at $x - 15/100 x$ = 0.85x

0.85x + $15/100$ × 0.85x = 1955

1.15 × 0.85 x = 1955

$x = {1955 × 10000}/{115 × 85}$= 2000

Discount is $15/100 × 2000$ = Rs. 300

Answer: (c)

Let cost price (C.P.) = Rs. x

& Marked price (M.P.) = Rs. 100

$x × 108/100$ = 90

$x = {90 × 100}/108$

New cost price : cost price

${90 × 100}/108$ : 100 = 5 : 6