mensuration area volumes Model Questions & Answers, Practice Test for ibps so prelims 2023

Question :26

The length of a cold storage is double its breadth. Its height is 3 metres. The area of its four walls (including the doors) is 108 $m^2$ . Find its volume.

Answer: (c)

Let l be the length and b be the breadth of cold storage.

L = 2B, H = 3 metres

Area of four walls = 2[L × H + B × H] = 108

⇒6BH = 108⇒B = 6

∴ L = 12, B = 6, H = 3

Volume = 12 × 6 × 3 = 216 $m^3$

Question :27

If the total surface area of a cube is 6 sq units, then what is the volume of the cube?

Answer: (b)

Total surface area of a cube = $6a^2$

⇒ 6 = $6a^2 ⇒ a^2$ = 1

∴ a = 1 unit

Volume of the cube = $a^3 = 1^3$ = 1 cu unit

Question :28

A cone of radius r cm and height h cm is divided into two parts by drawing a plane through the middle point of its height and parallel to the base. What is the ratio of the volume of the original cone to the volume of the smaller cone?

Answer: (c)

Let the cone is divided into two parts by a line l.

mensuration-area-and-volume-aptitude-mcq

Now triangle ACD and AOB are similar.

(According to proportionality theorem)

CD = $r/2, since AC = h/2$

Required ratio = ${\text"Volume of original cone"}/{\text"Volume of smaller cone"}$

= ${1/3 π r^2 h}/{1/3 π (r/2)^2 (h/2)} - 8/1$

∴ Required ratio = 8 : 1

Question :29

Suppose ABC is a triangle with AB of unit length D and E are the points lying on AB and AC respectively such that BC and DE are parallel. If the area of triangle ABC is twice the area of triangle ADE, then the length of AD is

Answer: (a)

We have BE || AC (Given)

So ∠ADE = ∠B and ∠AED = ∠C

(corresponding angles)

mensuration-area-and-volume-aptitude-mcq

Therefore ΔABC ∼ ΔADE by A similarity criterion. Also given area of ΔABC = 2 area of ΔADE ...(1) We know that the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.

⇒ ${ar (ABC)}/{ar (ADE)} = ({AB}/{AD})^2$ ...(2)

From (1) we get

${ar(ABC)}/{ar(ADE)} = 2/1$ ...(3)

Therefore from (2) and (3)

$({AB}/{AD})^2 = 2/1$

⇒ ${AB}/{AD} = √2/1$

⇒ $1/{AD} = √2 unit (∵ AB = 1 unit)$

AD = $1/√2$ units

∴ Option (a) is correct.

Question :30

Consider the following inequalities in respect of any triangle ABC : 1. AC – AB < BC 2. BC – AC < AB 3. AB – BC < ACWhich of the above are correct ?

Answer: (d)

In any triangle, sum of two sides is always greater than third side.

I. AC – AB < BC ⇒ AC < BC + AB {True}

II. BC – AC < AB ⇒ BC < AB + AC {True}

III. AB – BC < AC ⇒ AB < AC + BC {True}

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