time and distance Model Questions & Answers, Practice Test for ibps rrb clerk asst multipurpose prelims 2024

Answer: (a)

Speed of train

= ${\text"Length of train"}/{\text"Time taken to cross the stationary object"}$

∴ Length of train = Speed of train × Time taken to cross the stationary object

= ${72 × 1000 × 15}/{3600}$ = 300 m

Answer: (c)

Distance covered by A till 6pm = 60 km

Distance covered by A till 7pm = 120 km

Time taken by B to catch A = 60/(80 – 60) = 3 hrs

So A and B will meet at 6pm + 3 hrs = 9pm

Since we know that all three met at the some time

The time taken by C to cover 120 km difference will be

= 9pm – 7pm = 2hrs

Therefore, (x – 60) × 2 = 120

⇒2x – 120 = 120

2x = 240

∴ x = 120 km/hr.

Answer: (a)

Let total distance of the journey be x km.

first part of journey = $x/2$ km

Then second part of journey = $x/2$ km

According to question,

${x/2}/{30} + {x/2}/{70} = 10⇒{7x + 3x}/{210}$ = 20

∴ x = 2 × 210 = 420 km

Answer: (a)

Let the distance between be D km

Time taken by Radha – Time taken by Hema = 9 mins

So D/8 – D/10 = 9/60 hrs

${10D - 8D}/{80} = 9/{60}⇒{2D}/{80} = 9/{60}$

D = ${9 × 80}/{2 × 60}$ = 6km

Answer: (d)

Total distance travel by train

= length of platform + length of train

= 200 + 200 = 400 m

∴ Required speed = ${\text"Total distance travel"}/{\text"Time taken"}$

= ${400}/{15}$ m/s = ${400}/{15} × {18}/{5}$ km/h = 96 km/h