time and distance Model Questions & Answers, Practice Test for ibps rrb clerk asst multipurpose prelims 2024

Answer: (c)

Let speed of B = V

Then speed of A = $5/3$ V

Time taken by B to reach

winning post = $x/v$ ...(i)

Time taken by A to reach

winning post = ${x + 80}/v$ ...(ii)

Now, from eqs (i) and (ii)

⇒$x/v = {x + 80}/{{5v}/3}$⇒5x = 3x + 240 ; x = 120 km

Distance from starting point = x + 80

= 120 + 80 = 200 m

Answer: (a)

A : B = 1000 : 850 = 20 : 17

B : C = 2600 : 3000 = 13 : 15

⇒A : C = 20 × 13 : 15 × 17 = 52 : 51

Given, A runs 6000 m. = C runs = ${6000}/{52}$ × 51 = 5884.61

Hence A beats C by (60000 – 5884.61) = 115.39m

Answer: (b)

Here, we need to find the time that will take to cross 91 km stones completely.

Given that, in 1 hr. train travels 60 km i.e. 60 km is travelled in 60 min.

This means in 1 minute 1 km is travelled.

Therefore, 90 km is travelled in 90 minutes i.e. 1 hour 30 minutes and the remaining 1 km in 12 seconds.

Thus, The total time taken is 1 hr. 30 min. 12 sec.

Answer: (b)

Speed in still water = x km/h

Speed of stream = y km/h

Speed in down stream = (x + y) km/h

Speed in up stream = (x – y) km/h

Total time = Z hrs

Let distance be D km from each side

According to the question

$D/{x + y} + D/{x - y} = Z ; {Dx - Dy +Dx +Dy}/{x^2 - y^2} = Z$

2x × D = Z($x^2 – y^2)$

∴ D = ${Z(x^2 - y^2)}/{2x}$

Answer: (a)

Since distance is same in both ride than the average speed

= ${2xy}/{x + y} = {2 × 50 × 30}/{30 + 50} = {3000}/{80}$ = 37.5 km/hour