mensuration Model Questions & Answers, Practice Test for ibps clerk prelims 2024
ibps clerk prelims 2024 SYLLABUS WISE SUBJECTS MCQs
Ratio & Proportion
Percentage
Time & Work
Time & Distance
Mensuration
Trigonometric Ratios & Identities
A cylindrical rod of iron whose radius is one-fourth of its height is melted and cast into spherical balls of the same radius as that of the cylinder. What is the number of spherical balls?
Answer: (c)
Let the radius of cylindrical rod = r and height = 4r
∴ Required number of spherical balls
= ${\text"Volume of cylindrical rod"}/{\text"Volume of spherical balls"} = {πr^2 (4r)}/{4/3 πr^3}$ = 3
In which one of the following pairs does the first number represent the perimeter of one face of a cube and the second number represent the volume of the cube?
Answer: (c)
Let perimeter 4a = 20
⇒ a = 5
Volume of cube = $a^3$ = 125
Hence, pairs (20, 125), represents the perimeter of one face of a cube and volume of cube.
ΔABC is an isosceles triangle such that AB = BC = 8 cm and ∠ABC = 90°. What is the length of the perpendicular drawn from B on AC?
Answer: (c)
By using Pythagoras theorem in ΔABC.
$AC^2 = AB^2 + BC^2 = AC^2$ = 64 + 64
∴ $AC^2 = 8 √2$
ABC is isosceles right angle triangle, then
AP = PC = PB = ${AC}/2 = 4√2$
Two parallel chords of a circle whose diameter is 13 cm are respectively 5 cm and 12 cm in length. If both the chords are on the same side of the diameter, then the distance between these chords is
Answer: (a)
in ΔAPB
AB = ${13}/2$ cm, BP = ${12}/2$ = 6 cm
AP = ?
$AP^2 = AB^2 – BP^2$
$AP^2 = ({13}/2)^2 - ({12}/2)^2 = (5/2)^2$
AP = $5/2$
in ΔAQD
$AQ^2 = AD^2 – DQ^2$
= $({13}/2)^2 - (5/2)^2 = ({12}/2)^2$
AQ = ${12}/2$ = 6
PQ = 6 - $5/2 ⇒ 7/2$ = 3.5
A square is inscribed in a right-angled triangle with legs p and q, and has a common right angle with the triangle. The diagonal of the square is given by
Answer: (a)
Let length of the side of the square = x units
∴ Length of the diagonal = $√2$ x units
ΔADE ~ ΔEFC (By AAA)
∴ ${AD}/{EF} = {DE}/{FC}$
⇒ ${q - x}/x =x/{p - x}$
⇒ $x^2 = pq–px – qx + x^2$
⇒ x = ${pq}/{p + q}$
BE = ${√2 pq}/{p + q}$ Length of the diagonal
ibps clerk prelims 2024 IMPORTANT QUESTION AND ANSWERS
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