mensuration Model Questions & Answers, Practice Test for ibps clerk prelims 2024

Answer: (c)

Here OP is radius of circle and given triangle is equilateral.

∴ BP = $a/2$

In ΔBOP,

tan 30° = ${OP}/{BP}$

OP = BP tan 30

= $a/2 × 1/√3 = a/{2 √3}$ = radius.

Now, Area of circle = $πr^2$

154 = π × $(a/{2 √3})^2$

⇒ 154 = π $a^2/{12}$

⇒ 154 = ${22}/7 × a^2/{12}$

a = $√{7 × 7 × 12}$

= 7 × $2 √3 = 14 √3$

Perimeter of triangle = 3

= $3 × 14 √3 = 42 √3$

Answer: (d)

Total surface area = Curved surface area of cylinder + Curved surface area of cone + Top surface area of cylinder

= 2 πrh + πrl + π $r^2$

= π(2 × 3 × 4 × + $3 √{3^2 + 4^2} + 3^2$)

(∵l = $√{r^2 + h^2}$)

= π(24 + 15 + 9) = 48πsq cm

Answer: (d)

We know that, when two lines intersect each other it makes 4 angles.

The total number of pairs = 3

∴ Total number of angles = 3 × 4 = 12

Answer: (a)

OA and OB are radii of circle, AC and BC are tangents

Now, ∠AOB + ∠ACB = 180°

∠ACB = 180° – 130° = 50°

Answer: (a)

x + y + ${xy}/{100}$

= 100 + 100 + ${100 × 100}/{100}$

= 200 + 100 = 300%