Model 2 Vehicles in x/y of its usual speed Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 5 EXERCISES
The following question based on time & distance topic of quantitative aptitude
(a) 30 km/hr
(b) 25 km/hr
(c) 35 km/hr
(d) 17$6/7$ km/hr
The correct answers to the above question in:
Answer: (c)
1 hr 40 min 48 sec
= 1 hr $(40 + 48/60)$ min
= 1 hr $(40 + 4/5)$ min
= 1 hr $204/5$ min
= $(1 + 204/300)$ hr = $504/300$ hr
Speed = $42/{504/300}$ = 25 kmph
Now, $5/7$ usual speed = 25
Usual speed = ${25 × 7}/5$ = 35 kmph
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Read more usual vs actual speed Based Quantitative Aptitude Questions and Answers
Question : 1
Walking at three-fourth of his usual speed, a man covers a certain distance in 2 hours more than the time he takes to cover the distance at his usual speed. The time taken by him to cover the distance with his usual speed is
a) 5 hours
b) 6 hours
c) 5.5 hours
d) 4.5 hours
Answer »Answer: (b)
$4/3$ × usual time - usual time = 2
$1/3$ usual time = 2
Usual time = 2 × 3 = 6 hours
Using Rule 8,
Here, $\text"A"/ \text"B"= 3/4$, time= 2 hrs.
Usual Speed
= $\text"A"/\text"Diff of A and B"$ × time
= $3/{(4 - 3)} × 2$ = 6 hours
Question : 2
By walking at $3/4$ of his usual speed, a man reaches his office 20 minutes later than his usual time. The usual time taken by him to reach his office is
a) 30 minutes
b) 40 minutes
c) 60 minutes
d) 75 minutes
Answer »Answer: (c)
$4/3$ of usual time
= Usual time + 20 minutes
$1/3$ of usual time = 20 minutes
Usual time = 20 × 3 = 60 minutes
Using Rule 8,
Here, A = 3, B= 4, t = 20 minutes
Usual time taken
= $\text"A"/\text"Diff of A and B"$ × time
= $3/{(4 - 3)} × 20$ = 60 minutes
Question : 3
Walking at $6/7$th of his usual speed a man is 25 minutes late. His usual time to cover this distance is
a) 2 hours 10 minutes
b) 2 hours 25 minutes
c) 2 hours 15 minutes
d) 2 hours 30 minutes
Answer »Answer: (d)
Time and speed are inversely proportional.
$7/6$ × Usual time - Usual time = 25 minutes
Usual time $(7/6 -1)$
= 25 minutes
Usual time × $1/6$
= 25 minutes
Usual time = 25 × 6
= 150 minutes
= 2 hours 30 minutes
Using Rule 8,
Here, A = 6, B = 7, t = $25/60 = 5/12$ hrs.
Usual time = $\text"A"/\text"Diff of A and B"$ × time
= $6/{(7 - 6)} × 5/12 = 5/2$ hrs.
= 2 hours 30 minutes
Question : 4
A car goes 20 metres in a second. Find its speed in km/hr.
a) 20
b) 36
c) 72
d) 18
Answer »Answer: (c)
1 m/sec = $18/5$ kmph
20 m/sec = ${20 × 18}/5$
= 72 kmph
Question : 5
Walking at $3/4$ of his usual speed, a man is 1$1/2$ hours late. His usual time to cover the same distance, (in hours) is
a) 5
b) 5$1/2$
c) 4
d) 4$1/2$
Answer »Answer: (d)
Time and speed are inversely proportional.
$4/3$ of usual time –usual time = $3/2$
$1/3$ usual time = $3/2$
Usual time = ${3 × 3}/2$
$9/2 = 4{1}/2$ hours
Using Rule 8,
Here, A = 3, B = 4, t= $3/2$
Usual time = $\text"A"/\text"Diff of A and B"$ × time
= $3/{(4 - 3)} × 3/2 = 4{1}/2$ hrs.
Question : 6
A car covers four successive 7 km distances at speeds of 10 km/hour, 20 km/hour, 30 km/ hour and 60 km/hour respectively. Its average speed over this distance is
a) 40 km/hour
b) 60 km/hour
c) 20 km/hour
d) 30 km/hour
Answer »Answer: (c)
Total distance
= 7 × 4 = 28 km.
Total time
= $(7/10 + 7/20 + 7/30 + 7/60)$ hours
= $({42 + 21 + 14 + 7}/60)$ hours
= $84/60$ hours = $7/5$ hours
Average speed
= $\text"Total distance"/ \text"Total time" = (28/{7/5})$ kmph
= ${28 × 5}/7$ = 20 kmph
GET time & distance PRACTICE TEST EXERCISES
Model 1 Basic Time & Distance using formula
Model 2 Vehicles in x/y of its usual speed
Model 3 Problems on average speed
Model 4 Time & Distance with Ratios
Model 5 Problems with Races
time & distance Shortcuts and Techniques with Examples
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Model 1 Basic Time & Distance using formula
Defination & Shortcuts … -
Model 2 Vehicles in x/y of its usual speed
Defination & Shortcuts … -
Model 3 Problems on average speed
Defination & Shortcuts … -
Model 4 Time & Distance with Ratios
Defination & Shortcuts … -
Model 5 Problems with Races
Defination & Shortcuts …
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