Model 1 Train Vs Train in same direction Section-Wise Topic Notes With Detailed Explanation And Example Questions
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The following question based on trains topic of quantitative aptitude
(a) 190 m
(b) 200 m
(c) 150 m
(d) 100 m
The correct answers to the above question in:
Answer: (d)
Using Rule 12,If a train of length l m passes a bridge/platform of 'x' m in $t_1$ sec, then the time taken by the same train to cross another bridge/platform of length 'y' m is,Time taken = $({l + y}/{l + x})t_1$
Relative speed of police
= 11 – 10 = 1 kmph
= $5/18$ m/sec
Distance decreased in 6 minutes
= $5/18$ × 6 × 60 = 100 m
Distance remained between them
= 200–100 = 100 m
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Read more trains in same direction Based Quantitative Aptitude Questions and Answers
Question : 1
A train is moving at a speed of 80 km/h and covers a certain distance in 4.5 hours. The speed of the train to cover the same distance in 4 hours is
a) 70 km/h
b) 85 km/h
c) 90 km/h
d) 100 km/h
Answer »Answer: (c)
Distance = Speed × Time
= 80 × 4.5 = 360 km
∴ Required speed = $360/4$ = 90 kmph.
Question : 2
A moving train, 66 metres long, overtakes another train of 88 metres long, moving in the same direction in 0.168 minutes. If the second train is moving at 30 km/hr, at what speed is the first train moving ?
a) 50 km/hr.
b) 55 km/hr.
c) 25 km/hr.
d) 85 km/hr.
Answer »Answer: (d)
Suppose the speed of first train be x kmph
Speed of second train
= 30 kmph = ${30 × 1000}/60$
500 m per min.
According to question
$\text"Total Distance"/\text"Relativespeed"$
= $({66 + 88})/{x – 500} = 0.168$
$154/{x – 500} = 0.168$
0.168x – 84 = 154
0.168x = 238
$x = 238/0.168$
$({238 × 1000}/168)$m per minute
= ${238 × 1000}/168 × 3/50$ kmph = 85 kmph
Question : 3
Two trains, 80 metres and 120 metres long, are running at the speed of 25 km/hr and 35 km/hr respectively in the same direction on parallel tracks. How many seconds will they take to pass each other ?
a) 64
b) 70
c) 72
d) 48
Answer »Answer: (c)
Relative speed
= 35 – 25 = 10 kmph
= ${10 × 5}/18$ m/sec.
Total length = 80 + 120 = 200 metres
Required time
= $\text"Sum of the length of trains"/ \text"Relative speed"$
= $200/{{10 × 5}/18} = {200 × 18}/{10 × 5}$
= 72 seconds
Question : 4
Two trains travel in the same direction at the speed of 56 km/h and 29 km/h respectively. The faster train passes a man in the slower train in 10 seconds. The length of the faster train (in metres) is
a) 80
b) 75
c) 120
d) 100
Answer »Answer: (b)
Relative speed
= 56 – 29 = 27 kmph
= $27 × 5/18 = 15/2$ m/sec
Distance covered in 10 seconds
= $15/2$ × 10 = 75 m
Hence, length of train = 75 m.
Question : 5
Two trains, of same length, are running on parallel tracks in the same direction with speed 60 km/hour and 90 km/hour respectively. The latter completely crosses the former in 30 seconds. The length of each train (in metres) is
a) 150
b) 100
c) 115
d) 125
Answer »Answer: (d)
When two trains cross each other, they cover distance equal to the sum of their length with relative speed.
Let length of each train = x metre
Relative speed
= 90 – 60 = 30 kmph
= $({30 × 5}/18)$ m/sec.
= $(25/3)$ m/sec.
${2x}/{25/3} = 30$
2x = ${30 × 25}/3$
2x = 250
x = 125 metres
Question : 6
Two trains are running with speed 30 km/hr and 58 km/hr in the same direction. A man in the slower train passes the faster train in 18 seconds. The length (in metres) of the faster train is :
a) 100
b) 128
c) 140
d) 70
Answer »Answer: (c)
Relative speed
= (58 – 30) km/hr
= $(28 × 5/18)$ m/sec. = $70/9$ m/sec.
Length of train
= $70/9$ ×18 = 140 metres
trains Shortcuts and Techniques with Examples
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Model 1 Train Vs Train in same direction
Defination & Shortcuts … -
Model 2 Train Vs Train in opposite direction
Defination & Shortcuts … -
Model 3 Train Vs Bridge/Platform
Defination & Shortcuts … -
Model 4 Train Vs Pole/Signal Post/Man
Defination & Shortcuts … -
Model 5 Train Vs Both platform and a man/a pole
Defination & Shortcuts … -
Model 6 Change in speed Vs Change with time travel
Defination & Shortcuts …
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