model 3 successive discount Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 4 EXERCISES
The following question based on discount topic of quantitative aptitude
(a) 12%
(b) 28%
(c) 30%
(d) 15%
The correct answers to the above question in:
Answer: (b)
Using Rule 5,
Successive discounts of x% and y%
= $(x + y - {x + y}/100)%$
Required discount
= $(20 + 10 - {20 × 10}/100)$%
= 30 - 2 = 28%
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Read more problems on successive discount Based Quantitative Aptitude Questions and Answers
Question : 1
The marked price of a watch is Rs.1000. A retailer buys it at Rs.810 after getting two successive discounts of 10% and another rate which is illegible. What is the second discount rate?
a) 6.5%
b) 8%
c) 15%
d) 10%
Answer »Answer: (d)
Price after 10% first discount
= $1000 × {100 - 10}/100$
=$1000 × 90/100$ = Rs.900
Given :
Price after second discount = Rs.810
Second discount
= 900 - 810 = Rs.90
Percentage of second discount
= ${90 × 100}/900$ = 10%
Question : 2
A single discount equivalent to the successive discounts of 10%, 20% and 25% is
a) 60%
b) 46%
c) 55%
d) 45%
Answer »Answer: (b)
Single of discount for successive discounts 10% and 20%
= $(20 + 10 - {20 × 10}/100)$% = 28%
Equivalent discount for discounts 28% and 25%
= $(28 + 25 - {28 × 25}/100)$%
= 53 - 7 = 46%
Using Rule 4,If $D_1, D_2, D_3$ are successive discounts, then equivalent discount/overall discount is (in percentage)100 - $[({100 - D_1}/100)({100 - D_2}/100)({100 - D_3}/100) × 100]$
Single equivalent discount
= 100 - $[({100 - D_1}/100)({100 - D_2}/100)({100 - D_3}/100) × 100]$
= 100 - $[({100 - 10}/100)({100 - 20}/100)({100 - 25}/100) × 100]$
= $100 - 90/100 × 80/100 × 75/100 × 100$
= 100 - 54 = 46%
Question : 3
The marked price of a watch is Rs.800. A shopkeeper gives two successive discounts and sells the watch at Rs.612. If the first discount is 10%, the second discount is :
a) 20%
b) 15%
c) 10%
d) 12%
Answer »Answer: (b)
Let the second discount be x%.
Then, 90 % of (100 - x) % of 800 = 612
$90/100 × {100 - x}/100 × 800 = 612$
100 - x = ${612 × 100}/{90 × 8}$ = 85
x = 100 - 85 = 15%
Using Rule 3,
Here, M.P. = Rs.800, S.P. = Rs.612, $D_1 = 10%, D_2$ = ?
S.P. = M.P.$({100 - D_1}/100)({100 - D_2}/100)$
612 = 800 × $({100 - 10}/100) × ({100 - D_2}/100)$
612 = $800 × 90/100 × {100 - D_2}/100$
$6120/72 = 100 - D_2$
$D_2 = {100 - 6120}/72$
= ${7200 - 6120}/72$ = 15%
Question : 4
List price of an article at a show room is Rs.2,000 and it is being sold at successive discounts of 20% and 10%. Its net selling price will be :
a) Rs.1400
b) Rs.1440
c) Rs.1900
d) Rs.1700
Answer »Answer: (b)
Equivalent discount for successive discounts of 20% and 10%
= $[20 + 10 - {20 × 10}/100]%$ = 28%
Net selling price = 72% of 2000
= Rs.${72 × 2000}/100$ = Rs.1440
Using Rule 3,
Here, M.P. = Rs.2000, $D_1 = 20%, D_2$ = 10%
S.P. = M.P.$[({100 - D_1}/100)({100 - D_2}/100)]$
= M.P.$[2000 × ({100 - 20}/100) × ({100 - 10}/100)]$
= $2000 × {80 × 90}/10000$ = Rs.1440
Question : 5
Successive discounts of 10%, 20% and 30% is equivalent to a single discount of
a) 36%
b) 40.5%
c) 60%
d) 49.6%
Answer »Answer: (d)
Using Rule 5,
Single equivalent discount for successive discounts of 10% and 20%.
= $(10 + 20 - {20 × 100}/100)$% = 28%
Single equivalent discount for 28% and 30%.
= $(28 + 30 - {28 × 30}/100)$% = 49.6%
Question : 6
The list price of a clock is Rs.160. A customer buys it for Rs.122.40 after two successive discounts. If first discount is 10%, the second is
a) 18%
b) 15%
c) 10%
d) 12%
Answer »Answer: (b)
Marked price = Rs.160
After 10% discount
S.P = $90/100 × 160$ = Rs.144
Let other discount = x%
${(100 - x)}/100 × 144$ = Rs.122.40
100 - x = $12240/144$
100 - x = 85
x = 100 - 85 = 15%
Using Rule 3,
S.P. = M.P.$({100 - D_1}/100)({100 - D_2}/100)$
122.40 = 160$({100 - 10}/100)({100 - D_2}/100)$
${1224000}/160 = 90 × ({100 - D_2}/1)$
$1224000/{160 × 90} = 100 - D_2$
$85 = 100 - D_2 ⇒ D_2$ = 15%
GET discount PRACTICE TEST EXERCISES
model 1 profit x after discount y
model 2 hiking & discounting
model 3 successive discount
model 4 mixed discount problems of marked price
discount Shortcuts and Techniques with Examples
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