model 3 successive discount Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 4 EXERCISES
The following question based on discount topic of quantitative aptitude
(a) Rs.36
(b) Rs.34.80
(c) Rs.205.20
(d) Rs.204
The correct answers to the above question in:
Answer: (c)
A single discount equal to the two successive discounts
= $(10 + 5 - {10 × 5}/100)%$ = 14.5%
Selling price of the article
= 85.5% of Rs.240
= Rs.${85.5 × 240}/100$ = Rs.205.20
Using Rule 3,
Here, M.P. = Rs. 240, $D_1 = 10%, D_2$ = 5%
S.P. = M.P.$({100 - D_1}/100)({100 - D_2}/100)$
= $240({100 - 10}/100)({100 - 5}/100)$
= $240 × 90/100 × 95/100$
= Rs.205.20
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Read more problems on successive discount Based Quantitative Aptitude Questions and Answers
Question : 1
The list price of a clock is Rs.160. A customer buys it for Rs.122.40 after two successive discounts. If first discount is 10%, the second is
a) 18%
b) 15%
c) 10%
d) 12%
Answer »Answer: (b)
Marked price = Rs.160
After 10% discount
S.P = $90/100 × 160$ = Rs.144
Let other discount = x%
${(100 - x)}/100 × 144$ = Rs.122.40
100 - x = $12240/144$
100 - x = 85
x = 100 - 85 = 15%
Using Rule 3,
S.P. = M.P.$({100 - D_1}/100)({100 - D_2}/100)$
122.40 = 160$({100 - 10}/100)({100 - D_2}/100)$
${1224000}/160 = 90 × ({100 - D_2}/1)$
$1224000/{160 × 90} = 100 - D_2$
$85 = 100 - D_2 ⇒ D_2$ = 15%
Question : 2
Successive discounts of 10%, 20% and 30% is equivalent to a single discount of
a) 36%
b) 40.5%
c) 60%
d) 49.6%
Answer »Answer: (d)
Using Rule 5,
Single equivalent discount for successive discounts of 10% and 20%.
= $(10 + 20 - {20 × 100}/100)$% = 28%
Single equivalent discount for 28% and 30%.
= $(28 + 30 - {28 × 30}/100)$% = 49.6%
Question : 3
List price of an article at a show room is Rs.2,000 and it is being sold at successive discounts of 20% and 10%. Its net selling price will be :
a) Rs.1400
b) Rs.1440
c) Rs.1900
d) Rs.1700
Answer »Answer: (b)
Equivalent discount for successive discounts of 20% and 10%
= $[20 + 10 - {20 × 10}/100]%$ = 28%
Net selling price = 72% of 2000
= Rs.${72 × 2000}/100$ = Rs.1440
Using Rule 3,
Here, M.P. = Rs.2000, $D_1 = 20%, D_2$ = 10%
S.P. = M.P.$[({100 - D_1}/100)({100 - D_2}/100)]$
= M.P.$[2000 × ({100 - 20}/100) × ({100 - 10}/100)]$
= $2000 × {80 × 90}/10000$ = Rs.1440
Question : 4
The price of an article is raised by 30% and then two successive discounts of 10% each are allowed. Ultimately the price of the article is
a) decreased by 5.3%
b) decreased by 3%
c) increased by 10%
d) increased by 5.3%
Answer »Answer: (d)
Using Rule 5,
Let the original price be Rs.100
Increased price = Rs.130
Equivalent discount
= $(10 + 10 - {10 × 10}/100)$ = 19%
Ultimate price of the article = 81% of 130 = 105.3
i.e. increase by 5.3%.
Question : 5
A person paid Rs.17,000 for a motor-car after a single discount of 15%. If he is given successive discounts of 5% and 10% then how much he would pay ?
a) Rs.18,900
b) Rs.17,100
c) Rs.17,000
d) Rs.17,010
Answer »Answer: (b)
Let 'x' be the marked price Single Discount = 15%
100 - 15 = 85
85% of x = 17,000
$x = {17,000}/85 × 100$ = Rs.20,000
Required SP
= $20,000 × 95/100 × 90/100$
= 180 × 95 = Rs.17100
Using Rule 2,If article is sold on D% discount, thenSP = ${\text"MP"(100 - D)}/100$MP = ${\text"SP" × 100}/{100 - D}$
Using Rule 3,When successive Discounts $D_1, D_2, D_3$, so on, are given thenSP = MP$({100 - D_1}/100)({100 - D_2}/100)({100 - D_3}/100)$
M.P. = ${S.P. × 100}/{100 - D}$
= ${17000 × 100}/{100 - 15}$
= ${17000 × 100}/85$
M.P. = 20000
Also,
S.P. = M.P.$({100 - D_1}/100)({100 - D_2}/100)$
= 20000$({100 - 5}/100)({100 - 10}/100)$
= $20000 × 95/100 × 90/100$
= 180 × 95 = Rs.17100
Question : 6
A shopkeeper gives two successive discounts on an article marked Rs.450. The first discount given is 10 per cent. If the customer pays Rs.344.25 for the article, the second discount given is
a) 15 per cent
b) 12 per cent
c) 14 per cent
d) 10 per cent
Answer »Answer: (a)
Let the second discount be x per cent.
According to the question,
$450 × {100 - 10}/100 × {100 - x}/100$ = 344.25
100 - x = ${344.25 × 100 × 100}/{450 × 90}$
100 - x = 85
x = 100 - 85 = 15%.
Using Rule 3,
Here, M.P. = Rs.450, S.P. = Rs.344.25, $D_1 = 10%, D_2$ = ?
S.P. = M.P.$({100 - D_1}/100)({100 - D_2}/100)$
$344.25 = 450 × ({100 - 10}/100)({100 - D_2}/100)$
$3442500/{450 × 90} = (100 - D_2)$
$85 = 100 - D_2 ⇒ D_2$ = 15%
GET discount PRACTICE TEST EXERCISES
model 1 profit x after discount y
model 2 hiking & discounting
model 3 successive discount
model 4 mixed discount problems of marked price
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