model 3 successive discount Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 4 EXERCISES

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The following question based on discount topic of quantitative aptitude

Questions : A person paid Rs.17,000 for a motor-car after a single discount of 15%. If he is given successive discounts of 5% and 10% then how much he would pay ?

(a) Rs.18,900

(b) Rs.17,100

(c) Rs.17,000

(d) Rs.17,010

The correct answers to the above question in:

Answer: (b)

Let 'x' be the marked price Single Discount = 15%

100 - 15 = 85

85% of x = 17,000

$x = {17,000}/85 × 100$ = Rs.20,000

Required SP

= $20,000 × 95/100 × 90/100$

= 180 × 95 = Rs.17100

Using Rule 2,
If article is sold on D% discount, then
SP = ${\text"MP"(100 - D)}/100$
MP = ${\text"SP" × 100}/{100 - D}$

Using Rule 3,
When successive Discounts $D_1, D_2, D_3$, so on, are given then
SP = MP$({100 - D_1}/100)({100 - D_2}/100)({100 - D_3}/100)$

M.P. = ${S.P. × 100}/{100 - D}$

= ${17000 × 100}/{100 - 15}$

= ${17000 × 100}/85$

M.P. = 20000

Also,

S.P. = M.P.$({100 - D_1}/100)({100 - D_2}/100)$

= 20000$({100 - 5}/100)({100 - 10}/100)$

= $20000 × 95/100 × 90/100$

= 180 × 95 = Rs.17100

Practice discount (model 3 successive discount) Online Quiz

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Read more problems on successive discount Based Quantitative Aptitude Questions and Answers

Question : 1

The price of an article is raised by 30% and then two successive discounts of 10% each are allowed. Ultimately the price of the article is

a) decreased by 5.3%

b) decreased by 3%

c) increased by 10%

d) increased by 5.3%

Answer: (d)

Using Rule 5,

Let the original price be Rs.100

Increased price = Rs.130

Equivalent discount

= $(10 + 10 - {10 × 10}/100)$ = 19%

Ultimate price of the article = 81% of 130 = 105.3

i.e. increase by 5.3%.

Question : 2

An item is marked for Rs.240 for sale. If two successive discounts of 10% and 5% are allowed on the sale price, the selling price of the article will be

a) Rs.36

b) Rs.34.80

c) Rs.205.20

d) Rs.204

Answer: (c)

A single discount equal to the two successive discounts

= $(10 + 5 - {10 × 5}/100)%$ = 14.5%

Selling price of the article

= 85.5% of Rs.240

= Rs.${85.5 × 240}/100$ = Rs.205.20

Using Rule 3,

Here, M.P. = Rs. 240, $D_1 = 10%, D_2$ = 5%

S.P. = M.P.$({100 - D_1}/100)({100 - D_2}/100)$

= $240({100 - 10}/100)({100 - 5}/100)$

= $240 × 90/100 × 95/100$

= Rs.205.20

Question : 3

The list price of a clock is Rs.160. A customer buys it for Rs.122.40 after two successive discounts. If first discount is 10%, the second is

a) 18%

b) 15%

c) 10%

d) 12%

Answer: (b)

Marked price = Rs.160

After 10% discount

S.P = $90/100 × 160$ = Rs.144

Let other discount = x%

${(100 - x)}/100 × 144$ = Rs.122.40

100 - x = $12240/144$

100 - x = 85

x = 100 - 85 = 15%

Using Rule 3,

S.P. = M.P.$({100 - D_1}/100)({100 - D_2}/100)$

122.40 = 160$({100 - 10}/100)({100 - D_2}/100)$

${1224000}/160 = 90 × ({100 - D_2}/1)$

$1224000/{160 × 90} = 100 - D_2$

$85 = 100 - D_2 ⇒ D_2$ = 15%

Question : 4

A shopkeeper gives two successive discounts on an article marked Rs.450. The first discount given is 10 per cent. If the customer pays Rs.344.25 for the article, the second discount given is

a) 15 per cent

b) 12 per cent

c) 14 per cent

d) 10 per cent

Answer: (a)

Let the second discount be x per cent.

According to the question,

$450 × {100 - 10}/100 × {100 - x}/100$ = 344.25

100 - x = ${344.25 × 100 × 100}/{450 × 90}$

100 - x = 85

x = 100 - 85 = 15%.

Using Rule 3,

Here, M.P. = Rs.450, S.P. = Rs.344.25, $D_1 = 10%, D_2$ = ?

S.P. = M.P.$({100 - D_1}/100)({100 - D_2}/100)$

$344.25 = 450 × ({100 - 10}/100)({100 - D_2}/100)$

$3442500/{450 × 90} = (100 - D_2)$

$85 = 100 - D_2 ⇒ D_2$ = 15%

Question : 5

The marked price of a T.V. is Rs.16,000. After two successive discounts it is sold for Rs.11,400. If the first discount is 5%, then the rate of second discount is

a) 25%

b) 30%

c) 15%

d) 20%

Answer: (a)

After a discount of 5%

SP = ${95 × 16000}/100$ = Rs.15200

Let the second discount be x%.

x% of 15200 = (15200 - 11400)

${x × 15200}/100 = 3800$

$x = {3800 × 100}/15200 = 25$

Second discount = 25%

Using Rule 3,

Here, M.P. = 16000, S.P. = 11400, $D_1 = 5%, D_2$ = ?

S.P. = M.P.$({100 - D_1}/100)({100 - D_2}/100)$

11400 = 16000$({100 - 5}/100)({100 - D_2}/100)$

$114000/{16 × 95} = 100 - D_2$

$75 = 100 - D_2 ⇒ D_2$ = 25%

Question : 6

An article is listed at Rs.900 and two successive discounts of 8% and 8% are given on it. How much would the seller gain or lose, if he gives a single discount of 16%, instead of two discounts ?

a) Loss of Rs.4.76

b) Gain of Rs.5.76

c) Gain of Rs.4.76

d) Loss of Rs.5.76

Answer: (d)

Using Rule 5,

Equivalent discount for two successive discounts of 8% and 8%

= $(8 + 8 - {8 × 8}/100)$%

= (16–0.64) % = 15.36 %

SP = (100 –15.36) % of 900

= Rs.$({84.64 × 900}/100)$ = Rs.761.76

For a single discount of 16%,

SP = 84% of 900

= Rs.$({84 × 900}/100)$ = Rs.756

Certainly seller will lose in this case.

Loss = Rs. (761.76 - 756) = Rs.5.76

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