model 3 successive discount Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 4 EXERCISES
The following question based on discount topic of quantitative aptitude
(a) 25%
(b) 30%
(c) 15%
(d) 20%
The correct answers to the above question in:
Answer: (a)
After a discount of 5%
SP = ${95 × 16000}/100$ = Rs.15200
Let the second discount be x%.
x% of 15200 = (15200 - 11400)
${x × 15200}/100 = 3800$
$x = {3800 × 100}/15200 = 25$
Second discount = 25%
Using Rule 3,
Here, M.P. = 16000, S.P. = 11400, $D_1 = 5%, D_2$ = ?
S.P. = M.P.$({100 - D_1}/100)({100 - D_2}/100)$
11400 = 16000$({100 - 5}/100)({100 - D_2}/100)$
$114000/{16 × 95} = 100 - D_2$
$75 = 100 - D_2 ⇒ D_2$ = 25%
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Read more problems on successive discount Based Quantitative Aptitude Questions and Answers
Question : 1
A shopkeeper gives two successive discounts on an article marked Rs.450. The first discount given is 10 per cent. If the customer pays Rs.344.25 for the article, the second discount given is
a) 15 per cent
b) 12 per cent
c) 14 per cent
d) 10 per cent
Answer »Answer: (a)
Let the second discount be x per cent.
According to the question,
$450 × {100 - 10}/100 × {100 - x}/100$ = 344.25
100 - x = ${344.25 × 100 × 100}/{450 × 90}$
100 - x = 85
x = 100 - 85 = 15%.
Using Rule 3,
Here, M.P. = Rs.450, S.P. = Rs.344.25, $D_1 = 10%, D_2$ = ?
S.P. = M.P.$({100 - D_1}/100)({100 - D_2}/100)$
$344.25 = 450 × ({100 - 10}/100)({100 - D_2}/100)$
$3442500/{450 × 90} = (100 - D_2)$
$85 = 100 - D_2 ⇒ D_2$ = 15%
Question : 2
A person paid Rs.17,000 for a motor-car after a single discount of 15%. If he is given successive discounts of 5% and 10% then how much he would pay ?
a) Rs.18,900
b) Rs.17,100
c) Rs.17,000
d) Rs.17,010
Answer »Answer: (b)
Let 'x' be the marked price Single Discount = 15%
100 - 15 = 85
85% of x = 17,000
$x = {17,000}/85 × 100$ = Rs.20,000
Required SP
= $20,000 × 95/100 × 90/100$
= 180 × 95 = Rs.17100
Using Rule 2,If article is sold on D% discount, thenSP = ${\text"MP"(100 - D)}/100$MP = ${\text"SP" × 100}/{100 - D}$
Using Rule 3,When successive Discounts $D_1, D_2, D_3$, so on, are given thenSP = MP$({100 - D_1}/100)({100 - D_2}/100)({100 - D_3}/100)$
M.P. = ${S.P. × 100}/{100 - D}$
= ${17000 × 100}/{100 - 15}$
= ${17000 × 100}/85$
M.P. = 20000
Also,
S.P. = M.P.$({100 - D_1}/100)({100 - D_2}/100)$
= 20000$({100 - 5}/100)({100 - 10}/100)$
= $20000 × 95/100 × 90/100$
= 180 × 95 = Rs.17100
Question : 3
The price of an article is raised by 30% and then two successive discounts of 10% each are allowed. Ultimately the price of the article is
a) decreased by 5.3%
b) decreased by 3%
c) increased by 10%
d) increased by 5.3%
Answer »Answer: (d)
Using Rule 5,
Let the original price be Rs.100
Increased price = Rs.130
Equivalent discount
= $(10 + 10 - {10 × 10}/100)$ = 19%
Ultimate price of the article = 81% of 130 = 105.3
i.e. increase by 5.3%.
Question : 4
An article is listed at Rs.900 and two successive discounts of 8% and 8% are given on it. How much would the seller gain or lose, if he gives a single discount of 16%, instead of two discounts ?
a) Loss of Rs.4.76
b) Gain of Rs.5.76
c) Gain of Rs.4.76
d) Loss of Rs.5.76
Answer »Answer: (d)
Using Rule 5,
Equivalent discount for two successive discounts of 8% and 8%
= $(8 + 8 - {8 × 8}/100)$%
= (16–0.64) % = 15.36 %
SP = (100 –15.36) % of 900
= Rs.$({84.64 × 900}/100)$ = Rs.761.76
For a single discount of 16%,
SP = 84% of 900
= Rs.$({84 × 900}/100)$ = Rs.756
Certainly seller will lose in this case.
Loss = Rs. (761.76 - 756) = Rs.5.76
Question : 5
The marked price of watch was Rs.820. A man bought the watch for Rs.570.72 after getting two successive discounts, of which the first was 20%. The second discount was
a) 11%
b) 13%
c) 18%
d) 15%
Answer »Answer: (b)
Total discount
=Rs.(820 - 570.72) = Rs.249.28
First discount = $820 × 20/100$ = Rs.164
Second discount
= Rs.(249.28 - 164) = Rs.85.28
Price of the article after first discount
= Rs.(820 - 164) = Rs.656
If the second discount be x% , then
x% of 656 = 85.28
$x = {85.28 × 100}/656 = 13%$
Using Rule 3,
Here, M.P. = Rs.820, S.P. = 570.72, $D_1 = 20%, D_2$ = ?
S.P. = M.P.$({100 - D_1}/100)({100 - D_2}/100)$
$570.72 = 820 ({100 - 20}/100)({100 - D_2}/100)$
$5707200/{820 × 80} = 100 - D_2$
$100 - D_2 = 87 ⇒ D_2$ = 13%
Question : 6
An article listed at Rs.800 is sold at successive discounts of 25% and 15%. The buyer desires to sell it off at a profit of 20% after allowing a 10% discount. What would be his list price ?
a) Rs.680
b) Rs.640
c) Rs.620
d) Rs.600
Answer »Answer: (a)
Using Rule 5,
Effective discount
= 25 + 15 - ${25 × 15}/100$
= 40 - 3.75 = 36.25 %
CP for buyer
= (100 - 36.25) % of 800
= ${63.75 × 800}/100$ = Rs.510
To gain 20%,
SP = Rs.$({120 × 510}/100)$ = Rs.612
Let the list price be Rs.x.
90% of x = Rs.612
${90x}/100$ = 612
$x = 61200/90$ = Rs.680
GET discount PRACTICE TEST EXERCISES
model 1 profit x after discount y
model 2 hiking & discounting
model 3 successive discount
model 4 mixed discount problems of marked price
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