model 3 successive discount Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 4 EXERCISES
The following question based on discount topic of quantitative aptitude
(a) 18%
(b) 15%
(c) 12%
(d) 14%
The correct answers to the above question in:
Answer: (b)
Marked price = Rs.720
Actual price = Rs.550.80
First discount = 10%
Let the second discount be x%
Then, we can write
720 (1 - 0.10) (1–0.01x) = 550.80
720 × 0.9 (1– 0.01x) = 550.8
648 (1 - 0.01x) = 550.8
1 - 0.01 x= ${550.8}/648$
0.01 x = $1 - {550.8}/648$
$x = {1 - 0.85}/{0.01}$
x = 0.15 × 100 ⇒ x= 15
Second discount = 15%
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Read more problems on successive discount Based Quantitative Aptitude Questions and Answers
Question : 1
The marked price of an article is Rs.500. It is sold at successive discounts of 20% and 10%. The selling price of the article (in rupees) is :
a) 400
b) 360
c) 350
d) 375
Answer »Answer: (b)
Equivalent discount of successive discounts of 20% and 10%
= $(20 + 10 - {20 × 10}/100)$% = 28%
Selling Price = (100 - 28) % of Rs.500 = 72 % of 500
= Rs.${500 × 72}/100$ = Rs.360
Using Rule 3,When successive Discounts $D_1, D_2, D_3$, so on, are given thenSP = MP$({100 - D_1}/100)({100 - D_2}/100)({100 - D_3}/100)$
M.P. = Rs.500, $D_1 = 20%, D_2$ = 10%
S.P.= M.P.$({100 - D_1}/100)({100 - D_2}/100)$
= $500({100 - 20}/100)({100 - 10}/100)$
= $500 × 80/100 × 90/100$ = Rs.360
Question : 2
If on a marked price, the difference of selling prices with a discount of 30% and two successive discounts of 20% and 10% is Rs.72, then the marked price (in rupees) is
a) 2,400
b) 2,500
c) 3,600
d) 3,000
Answer »Answer: (c)
Using Rule 5,
Let the marked price be Rs.x.
In case I, SP = Rs.${70x}/100$
Single discount equivalent to successive discounts of 20% and 10%.
= $(20 + 10 - {20 × 10}/100)$% = 28%
S.P. in this case = ${72x}/100$
${72x}/100 - {70x}/100$ = 72
${2x}/100 = 72$
$x = {72 × 100}/2$ = Rs.3600
Question : 3
An article listed at Rs.800 is sold at successive discounts of 25% and 15%. The buyer desires to sell it off at a profit of 20% after allowing a 10% discount. What would be his list price ?
a) Rs.680
b) Rs.640
c) Rs.620
d) Rs.600
Answer »Answer: (a)
Using Rule 5,
Effective discount
= 25 + 15 - ${25 × 15}/100$
= 40 - 3.75 = 36.25 %
CP for buyer
= (100 - 36.25) % of 800
= ${63.75 × 800}/100$ = Rs.510
To gain 20%,
SP = Rs.$({120 × 510}/100)$ = Rs.612
Let the list price be Rs.x.
90% of x = Rs.612
${90x}/100$ = 612
$x = 61200/90$ = Rs.680
Question : 4
An article is listed at Rs.920. A customer pays Rs.742.90 for it after getting two successive discounts. If the rate of first discount is 15%, the rate of 2nd discount is
a) 12%
b) 8%
c) 3%
d) 5%
Answer »Answer: (d)
Total discount
= Rs.(920 - 742.90) = Rs.177.10
First discount = 15%
Discount = 15% of 920
= ${920 × 15}/100$ = Rs.138
Price after this discount
= 920 - 138 = Rs.782
Remaining discount
= 177.10 - 138 = Rs.39.10
Let the second discount be x %.
${782 × x}/100 = 39.10$
$x = {39.10 × 100}/782$ = 5%
Using Rule 3,
Here, M.P. = Rs.920, S.P. = Rs.742.90, $D_1 = 15%, D_2$ = ?
S.P. = M.P.$({100 - D_1}/100)({100 - D_2}/100)$
742.90 = 920 $({100 - 15}/100)({100 - D_2}/100)$
$7429000/{920 × 85} = 100 - D_2$
95 = 100 - $D_2 ⇒ D_2$ = 5%
Question : 5
The difference between a single discount of 30% on Rs.550 and two successive discounts of 20% and 10% on the same amount is
a) Rs.44
b) Rs.22
c) Nil
d) Rs.11
Answer »Answer: (d)
Using Rule 5,(Special Case) : When two successive disounts are given, then overall discount is =$(D_1 + D_2 - {D_1D_2}/100)%$
Case I : A single discount of 30%
Case II : Two successive discounts of 20% and 10% Single equivalent discount
= $(20 + 10 - {20 × 10}/100)$% = 28%
Difference = (30 - 28)% = 2%
Required difference
= 2% of 550
=Rs. ${2 × 550}/100$ = Rs.11.
Question : 6
Two successive discounts of 20% and 20% is equivalent to a single discount of
a) 34%
b) 36%
c) 42%
d) 40%
Answer »Answer: (b)
Using Rule 5,
Equivalent single discount
= $(20 + 20 - {20 × 20}/100)$% = 36%
GET discount PRACTICE TEST EXERCISES
model 1 profit x after discount y
model 2 hiking & discounting
model 3 successive discount
model 4 mixed discount problems of marked price
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