Model 1 Simplification using VBODMAS Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 4 EXERCISES
The following question based on simplification topic of quantitative aptitude
(a) $2/3$
(b) 2
(c) $1/2$
(d) 1
The correct answers to the above question in:
Answer: (b)
Using Rule 1,
$2/3 × 3/{5/6 ÷ {2/3} of 1{1/4}}$
$2/3 × 3/{5/6 ÷ {2/3} of {5/4}}$
$2/3 × 3/{{5/6} ÷ {10/12}}$
= $2/3 × 3/{5/6 × 12/10} = 2/3 × 3/1 = 2$
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Read more problems based on vbodmas Based Quantitative Aptitude Questions and Answers
Question : 1
If ${1120}/{√{P}}$ = 80, then P is equal to
a) 225
b) 14
c) 196
d) 140
Answer »Answer: (c)
80 × $√{P}$ = 1120
$√{P} = 1120/80 = 14$
P = $(14)^2 = 196$
Question : 2
Simplify : ${2{3/4}}/{1{5/6}} ÷ {7/8} × (1/3 + 1/4) + 5/7 ÷ {3/4} of {3/7}$
a) 3$2/9$
b) $56/77$
c) $2/3$
d) $49/80$
Answer »Answer: (a)
Using Rule 1,
The given expression
${2{3/4}}/{1{5/6}} ÷ {7/8} × (1/3 + 1/4) + 5/7 ÷ {3/4} of {3/7}$
= ${11/4}/{11/6} ÷ {7/8} × ({4+3}/12) + 5/7 ÷ {3/4} of {3/7}$
= $(11/4 × 6/11) ÷ {7/8} × 7/12 + 5/7 ÷ (3/4 × 3/7)$
= ${3/2} ÷ {7/8} × 7/12 + {5/7} ÷ {9/28}$
= ${3/2} × {8/7} × 7/12 + {5/7} ×{28/9}$
= $1 + 20/9 = {9+20}/9 = 29/9 = 3{2}/9$
Question : 3
1– [5 - {2 + (– 5 + 6 - 2) 2}] is equal to :
a) –2
b) –4
c) 0
d) 2
Answer »Answer: (b)
Using Rule 1,
? = 1 - [5 - {2 + (–1)2}]
= 1 - [5 - {2 - 2}]
= 1 - [5 - 0]
= 1 - 5 = - 4
Question : 4
5 - [4 - {3 - (3 - 3 - 6)}] is equal to :
a) 0
b) 10
c) 4
d) 6
Answer »Answer: (b)
Using Rule 1,
An expression must be simplified by following defined order/sequence known as VBODMAS, which is given by:
| 1st step, | V | - | Vineculum (line brackets)/Bar |
| B | - | Brackets | |
| O | - | Of | |
| D | - | Division | |
| M | - | Multiplication | |
| A | - | Addition | |
| Last step, | S | - | Subtraction |
There are four types of brackets given below.
- – → Line/Bar
- ( ) → Simple or Small Bracket/open brackets
- { } → Curly Brackets/Braces
- [ ] → Square Brackets/Closed brackets
These brackets must be solved in given order only.
? = 5 - [4 - {3 - (3– 3 - 6)}]
= 5 - [4 - { 3 - (– 6)}]
= 5 - [4 - {3 + 6}]
= 5 - [4 - 9]
= 5 + 5 = 10
Question : 5
$9 - 1{2/9} of 3{3/11} ÷ 5{1/7} of {7/9}$ is equal to :
a) $3/4$
b) 8
c) 8$32/81$
d) 9
Answer »Answer: (b)
Using Rule 1,
Expression
= $9 - 11/9 of {36/11} ÷ {36/7} of 7/9$
= $9 - 11/9 × {36/11} ÷ {36/7} × 7/9$
= 9 - 4 ÷ 4
= $9 - 4 × 1/4$ = 9 - 1 = 8
Question : 6
$1/30 + 1/42 + 1/56 + 1/72 + 1/90 + 1/110$ = ?
a) $6/55$
b) $√{2}2/27$
c) $5/27$
d) $1/9$
Answer »Answer: (a)
Using Rule 2,
$1/{5×6} + 1/{6×7} + 1/{7×8} + 1/{8×9} + 1/{9×10} + 1/{10×11}$
= $1/5 - 1/6 + 1/6 - 1/7 + 1/7 - 1/8 + 1/8 - 1/9 +1/9 - 1/10 +1/10 - 1/11 +1/11$
= $1/5 - 1/11 ={11 - 5}/55 = 6/55$
GET simplification PRACTICE TEST EXERCISES
Model 1 Simplification using VBODMAS
Model 2 Simplification based on square & square root
Model 3 Simplification based on cube & cube root
Model 4 Simplification with continued fraction
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