Model 3 Opening both taps and leaks Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 3 EXERCISES
The following question based on pipes & cisterns topic of quantitative aptitude
(a) 12 minutes
(b) 10 minutes
(c) 5 minutes
(d) 8 minutes
The correct answers to the above question in:
Answer: (d)
Let the first pipe be closed after x minutes
$x/20 + 18/30$ = 1
$x/20 = 1 - 18/30 = 1 - 3/5 = 2/5$
$x = 2/5 × 20$ = 8 minutes
Using Rule 8,Two taps A and B can fill a tank in x hours and y hours respectively. If both the pipes are opened together, then the time after which pipe B should be closed so that the tank is full in t hoursRequired time = $[y(1 –{t/x})]$ hours
Here, x = 20, y = 30, t = 18
Required time = $[x(1 –{t/y})]$
[Since, first pipe is closed]
= $[20(1 - 18/30)] = 20 × 12/30$ = 8 minutes
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Read more opening both taps and leaks Based Quantitative Aptitude Questions and Answers
Question : 1
A water tap fills a tub in ‘p’ hours and a sink at the bottom empties it in ‘q’ hours. If p < q and both tap and sink are open, the tank is filled in ‘r’ hours; then
a) r = p - q
b) r = p + q
c) $1/r = 1/p + 1/q$
d) $1/r = 1/p - 1/q$
Answer »Answer: (d)
Since, P < q,
On opening pipe and sink together,
Part of the tub filled in 1 hour
= $1/P - 1/q$
Clearly, $1/P - 1/q = 1/r$
Question : 2
Two pipes A and B can fill a tank in 6 hours and 8 hours respectively. If both the pipes are opened together, then after how many hours should B be closed so that the tank is full in 4 hours?
a) $8/3$ hrs
b) 2 hrs
c) $2/3$ hrs
d) 1hrs
Answer »Answer: (a)
Part of the tank filled in 4 hours by pipe A = $4/6 = 2/3$
Remaining part = ${1 - 2}/3 = 1/3$
Time taken by pipe B in filling $1/3$ part = $8/3$ hours
Using Rule 8,
Here, x = 6, y = 8, t = 4
Required time = $[y(1 –{t/x})]$ hours
= $[8(1 - 4/6)]$ hours = $8/3$ hours
Question : 3
A tank can be filled with water by two pipes A and B together in 36 minutes. If the pipe B was stopped after 30 minutes, the tank is filled in 40 minutes. The pipe B can alone fill the tank in
a) 90 minutes
b) 75 minutes
c) 45 minutes
d) 60 minutes
Answer »Answer: (a)
Let the pipe B fill the tank in x minutes.
Part of the tank filled by pipes A and B in 1 minute = $1/36$
Part of the tank filled by pipe A in 1 minute
= $1/36 - 1/x$
According to the question,
30 × $1/x + 40(1/36 - 1/x) = 1$
$30/x + 10/9 - 40/x$ = 1
$40/x - 30/x = 10/9 - 1$
$10/x = 1/9 ⇒ x = 90$ minutes
GET pipes & cisterns PRACTICE TEST EXERCISES
Model 1 Basic Pipes & Cisterns problems
Model 2 Filling tank by parts or fractions
Model 3 Opening both taps and leaks
pipes & cisterns Shortcuts and Techniques with Examples
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