Model 3 Opening both taps and leaks Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 3 EXERCISES
The following question based on pipes & cisterns topic of quantitative aptitude
(a) 100 hours
(b) 90 hours
(c) 70 hours
(d) 80 hours
The correct answers to the above question in:
Answer: (b)
Using Rule 7,
Part of the tank emptied by the leak in 1 hour
= $1/9 - 1/10 = {10 - 9}/90 = 1/90$
Required time = 90 hours
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Read more opening both taps and leaks Based Quantitative Aptitude Questions and Answers
Question : 1
A cistern is normally filled in 8 hours but takes another 2 hours longer to fill because of a leak in its bottom. If the cistern is full, the leak will empty it in :
a) 40 hours
b) 25 hours
c) 16 hours
d) 20 hours
Answer »Answer: (a)
Using Rule 7,
Part emptied by the leak in 1 hour
= $1/8 - 1/10 = {5 - 4}/40 = 1/40$
The leak will empty the cistern in 40 hours.
Question : 2
A pipe can fill a tank in 24 hrs. Due to a leakage in the bottom, it is filled in 36 hrs. If the tank is half full, how much time will the leak take to empty the tank?
a) 24 hrs
b) 36 hrs
c) 48 hrs
d) 72 hrs
Answer »Answer: (b)
Using Rule 7,
Part of tank emptied by leak in an hour
= $1/36 - 1/24 = {2 - 3}/72 = {–1}/72$
Time taken in emptying the full tank
= 72 hours
Required time = 36 hours
Question : 3
A tap can fill a cistern in 40 minutes and a second tap can empty the filled cistern in 60 minutes. By mistake without closing the second tap, the first tap was opened. In how many minutes will the empty cistern be filled ?
a) 120
b) 108
c) 72
d) 84
Answer »Answer: (a)
Using Rule 7,
Tricky Approach
Part of the cistern filled in 1 minute by both the taps
= $1/40 - 1/60 = {3 - 2}/120 = 1/120$
Empty cistern will be filled in 120 minutes.
Question : 4
A tank is fitted with two taps. The first tap can fill the tank completely in 45 minutes and the second tap can empty the full tank in one hour. If both the taps are opened alternately for one minute, then in how many hours the empty tank will be filled completely ?
a) 5 hours 53 minutes
b) 4 hours 48 minutes
c) 2 hours 55 minutes
d) 3 hours 40 minutes
Answer »Answer: (a)
Using Rule 7,
Part of the tank filled in one minute
= $1/45 - 1/60 = {4 - 3}/180 = 1/180$
Since, $1/180$ part is filled in 1 minute
$1 - 1/45 = 44/45$ part is filled in
${2 × 180 × 44}/45$ = 352 minutes
i.e. 5 hours 52 minutes
Remaining $1/45$ part will be filled in 1 minute.
Total time taken = 5 hours 53 minutes
Question : 5
Pipe A can fill a tank in 4 hours and pipe B can fill it in 6 hours. If they are opened on alternate hours and if pipe A is opened first, in how many hours, the tank shall be full ?
a) 4$2/3$
b) 3$1/4$
c) 4$1/2$
d) 3$1/2$
Answer »Answer: (a)
Using Rule 1,Two taps 'A' and 'B' can fill a tank in 'x' hours and 'y' hours respectively. If both the taps are opened together, then how much time it will take to fill the tank?Required time = $({xy}/{x + y})$ hrs
Part of tank filled in first two hours
= $1/4 + 1/6 = {3 + 2}/12 = 5/12$
Part of tank filled in first 4 hours
= $10/12 = 5/6$
Remaining part = $1 - 5/6 = 1/6$
This remaining part willl be filled by pipe A.
Time taken by pipe A
= $1/6 × 4 = 2/3$ hour
Total time = 4 + $2/3 = 4{2}/3$ hours
Question : 6
A leak in the bottom of a tank can empty the full tank in 6 hours. An inlet pipe fills water at the rate of 4 litres a minute. When the tank is full, the inlet is opened and due to the leak the tank is empty in 8 hours. Find the capacity of the tank.
a) 24 litres
b) 10 litres
c) 5760 litres
d) 96 litres
Answer »Answer: (c)
Using Rule 7,
Part of tank filled by inlet pipe in 1 hour
= $1/6 - 1/8 = {4 - 3}/24 = 1/24$
Hence, if there is no leak, the inlet pipe will fill the tank in 24 hours.
Capacity of the tank
= 24 × 60 × 4 = 5760 litres
GET pipes & cisterns PRACTICE TEST EXERCISES
Model 1 Basic Pipes & Cisterns problems
Model 2 Filling tank by parts or fractions
Model 3 Opening both taps and leaks
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