model 4 mixed discount problems of marked price Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 4 EXERCISES

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The following question based on discount topic of quantitative aptitude

Questions : After allowing a discount of 12% on the marked price of an article, it is sold for Rs.880. Find its marked price.

(a) Rs.2,000

(b) Rs.1,100

(c) Rs.2,100

(d) Rs.1,000

The correct answers to the above question in:

Answer: (d)

Marked price

= $100/{100 - 12} × 880$ = Rs.1000

Using Rule 2,

Here, S.P. = Rs.880, D = 12%, M.P. = ?

M.P. = $\text"S.P. × 100"/{100 - D}$

= ${880 × 100}/{100 - 12}$ = Rs.1000

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Read more mixed problems on marked price Based Quantitative Aptitude Questions and Answers

Question : 1

When a shopkeeper gives 10% discount on the list price of a toy, his gain is 20%. If he had given a discount of 20%, his percentage of gain would have been

a) 8$1/3$%

b) 6$2/3$%

c) 15%

d) 10%

Answer: (b)

Let the cost price of toy be Rs.100 and the marked price be x.

${x × 90}/100 = 120$

$x = {120 × 100}/90$ = Rs.$400/3$

S.P. after a discount of 20%

= 80% of $400/3$

= ${400 × 80}/300 = 320/3 = 106{2}/3$

Profit percent

=$106{2}/3 - 100 = 6{2}/3$%

Question : 2

An article is sold at a discount of 20% and an additional discount of 30% is allowed on cash payment. If Vidya purchased the article by paying Rs.2240 in cash, the marked price of the article was

a) Rs.4368

b) Rs.4000

c) Rs.4480

d) Rs.4400

Answer: (b)

Let the marked price of the article be x.

Equivalent discount for successive discounts of 30% and 20%

= $(30 + 20 - {30 × 20}/100)$%

= (50 - 6)% = 44%

(100 - 44)% of x = 2240

${x × 56}/100 = 2240$

$x = {2240 × 100}/56$ = Rs.4000

Question : 3

A trader gains 15% after selling an item at 10% discount on the printed price. The ratio of the cost price and printed price of the item is

a) 17 : 18

b) 18 : 23

c) 18 : 25

d) 17 : 23

Answer: (b)

Let the CP of article be x and its marked price be y.

According to the question,

90% of y = 115% of x

${y × 90}/100 = {x × 115}/100$

$x/y =90/115 = 18/23$ ⇒ 18 : 23

Using Rule 6,

Here, r = 15%, D = 10%

$\text"MP"/\text"CP" = {100 + r}/{100 - D}$

= ${100 + 15}/{100 - 10}$

$\text"M.P."/ \text"C.P."= 115/90$

$\text"C.P."/ \text"M.P."= 90/115$

$\text"C.P."/ \text"M.P."= 18/23$

C.P. : M.P. = 18 : 23

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