Model 3 Man leaves & joins Section-Wise Topic Notes With Detailed Explanation And Example Questions
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The following question based on time & work topic of quantitative aptitude
(a) 8 days
(b) 12 days
(c) 15 days
(d) 10 days
The correct answers to the above question in:
Answer: (b)
Work done by (A + B) in 1 day
= $1/15 + 1/10 = {2 + 3}/30 = 5/30 = 1/6$
(A + B)’s 2 days’ work = $2/6 = 1/3$
Remaining work = $1 - 1/3 = 2/3$
This part is done by A alone.
Since, one work is done by A in 15 days.
$2/3$ work is done in $15 × 2/3$ = 10 days.
Total number of days = 10 + 2 = 12 days
Using Rule 20,
Here, m = 15, n = 10, p =2
A alone completed the work in
= $\text"mn - p(m+n)"/ \text"n"$days
= ${15 × 10 - 2(15 + 10)}/10$
= ${150 - 50}/10$ = 10 days
Total time taken= 10 + 2 = 12 days
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Read more man leaves and joins Based Quantitative Aptitude Questions and Answers
Question : 1
A and B working separately can do a piece of work in 10 days and 15 days respectively. If they work on alternate days beginning with A, in how many days will the work be completed ?
a) 13 days
b) 12 days
c) 6 days
d) 18 days
Answer »Answer: (b)
Work done by 2 (A + B) in one day
= $1/10 + 1/15 = {3 + 2}/30 = 5/30 = 1/6$
Work done by (A + B) in one day = $1/12$
(A + B) can complete the work in 12 days
Question : 2
A and B can do a piece of work in 30 days while B and C can do the same work in 24 days and C and A in 20 days. They all work together for 10 days when B and C leave. How many days more will A take to finish the work ?
a) 24 days
b) 30 days
c) 36 days
d) 18 days
Answer »Answer: (d)
(A + B)’s day’s work = $1/30$
(B + C)’s 1 day’s work = $1/24$
(C + A)’s 1 day’s work = $1/20$
2 (A + B + C)’s 1 day’s work = $1/30 + 1/24 + 1/20$
= ${4 + 5 + 6}/120 = = 15/120 = 1/8$
(A + B + C)’s 1 day’s work = $1/16$
(A + B + C)’s 10 days’ work = $10/16 = 5/8$
Remaining work = $1- 5/8 = 3/8$
This part of work is done by A alone.
Now A’s 1 day’s work = $1/16 - 1/24$
= ${3 - 2}/48 = 1/48$
The required no. of days
=$3/8 × 48$ = 18 days
Question : 3
A can do a piece of work in 20 days which B can do in 12 days. B worked at it for 9 days. A can finish the remaining work in
a) 7 days
b) 11 days
c) 3 days
d) 5 days
Answer »Answer: (d)
Work done by B in 9 days = $9/12 = 3/4$ part
Remaining work
= $1 - 3/4 = 1/4$ which is done by A
Time taken by A = $1/4 × 20$ = 5 days
time & work Shortcuts and Techniques with Examples
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Model 1 Basics on Time & Work
Defination & Shortcuts … -
Model 2 Formula method ‘M1D1W1 = M2D2W2’
Defination & Shortcuts … -
Model 3 Man leaves & joins
Defination & Shortcuts … -
Model 4 Working with Man, Woman, Child
Defination & Shortcuts … -
Model 5 Split & Fraction of work
Defination & Shortcuts … -
Model 6 Efficiency of the worker
Defination & Shortcuts … -
Model 7 Working with individual wages
Defination & Shortcuts …
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