Model 2 Filling tank by parts or fractions Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 3 EXERCISES
The following question based on pipes & cisterns topic of quantitative aptitude
(a) 6 hours
(b) 13$1/3$ hours
(c) 3$1/3$ hours
(d) 10 hours
The correct answers to the above question in:
Answer: (d)
Part of cistern emptied in 1 hour
= $1/5 - 1/8 = {8 - 5}/40 = 3/40$
Since, $3/40$ part is emptied in 1 hour.
$3/4$ part is emptied in
$40/3 × 3/4$ = 10 hours.
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Read more filling tank by parts or fractions Based Quantitative Aptitude Questions and Answers
Question : 1
A tap can fill an empty tank in 12 hours and another tap can empty half the tank in 10 hours. It both the taps are opened simultaneously, how long would it take for the empty tank to be filled to half its capacity ?
a) 15 hours
b) 30 hours
c) 12 hours
d) 20 hours
Answer »Answer: (b)
Using Rule 7,A tap 'A' can fill a tank in 'x' hours and 'B' can empty the tank in 'y' hours. Then (a) time taken to fill the tankwhen both are opened = $({xy}/{x - y})$ : x > yb) time taken to empty the tankwhen both are opened = $({xy}/{y- x})$ : y > x
Part of the tank filled in 1 hour
= $1/12 - 1/20 = {5 - 3}/60 = 1/30$
Tank will be filled in 30 hours.
Question : 2
If $1/3$ of a tank holds 80 litres of water, then the quantity of water that $1/2$ tank holds is :
a) $80/3$ litres
b) 240 litres
c) 100 litres
d) 120 litres
Answer »Answer: (d)
Let the capacity of the tank be x litres then
$x/3$ = 80 ⇒ x = 240
$x/2 = 240/2$ = 120 litres
Question : 3
Three pipes A, B and C can fill a tank in 6 hours, 9 hours and 12 hours respectively. B and C are opened for half an hour, then A is also opened. The time taken by the three pipes together to fill the remaining part of the tank is
a) 2$1/2$ hours
b) 3 hours
c) 3$1/2$ hours
d) 2 hours
Answer »Answer: (a)
Using Rule 1 and 2,
Part of the tank filled by B and C in half an hour
= $1/2(1/9 + 1/12)$
= $1/2({4 + 3}/36) = 7/72$
= Remaining part
= $1 - 7/72 = {72 - 7}/72 = 65/72$
Part of tank filled by three pipes in an hour
= $1/6 + 1/9 + 1/12$
= ${6 + 4 + 3}/36 = 13/36$
Time to fill remaining part
= $65/72 × 36/13 = 5/2 = 2{1}/2$ hours
GET pipes & cisterns PRACTICE TEST EXERCISES
Model 1 Basic Pipes & Cisterns problems
Model 2 Filling tank by parts or fractions
Model 3 Opening both taps and leaks
pipes & cisterns Shortcuts and Techniques with Examples
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