Model 4 Train Vs Pole/Signal Post/Man Section-Wise Topic Notes With Detailed Explanation And Example Questions
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The following question based on trains topic of quantitative aptitude
(a) 5 seconds
(b) 12.5 seconds
(c) 3$5/4$ seconds
(d) 2.5 seconds
The correct answers to the above question in:
Answer: (d)
Using Rule 1,
Speed of the train = 144 kmph
= $144 × 5/18$ = 40 m/s
When a train crosses a pole, it covers a distance equal to its own length.
The required time
= $100/40 = 5/2$ = 2.5 seconds.
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Read more crossing pole signal post man Based Quantitative Aptitude Questions and Answers
Question : 1
A train, 120 m long, takes 6 seconds to pass a telegraph post; the speed of train is
a) 62 km/hr
b) 55 km/hr
c) 85 km/hr
d) 72 km/hr
Answer »Answer: (d)
Using Rule 1,
Speed of train
= $\text"Length of train"/ \text"Time taken in crossing the pole"$
= $120/6$ = 20 m/sec
= 20 × $18/5$ = 72 kmph
Question : 2
Buses start from a bus terminal with a speed of 20 km/hr at intervals of 10 minutes. What is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at intervals of 8 minutes?
a) 4 km/hr
b) 5 km/hr
c) 7 km/hr
d) 3 km/hr
Answer »Answer: (b)
Distance covered in 10 minutes at 20kmph
= distance covered in 8 minutes at (20 + x ) kmph
20 × $10/60 = 8/60 (20 + x)$
200 = 160 + 8x
8x = 40 ⇒ $x = 40/8$ = 5 kmph
Question : 3
A train 150m long passes a telegraphic post in 12 seconds. Find the speed of the train.(in km/hr)
a) 12.5
b) 25
c) 45
d) 50
Answer »Answer: (c)
Distance covered by train in crossing a telegraphic post
= length of train
Speed of train = $\text"Distance"/ \text"Time"$
= $(150/12)$ m./sec.
= $(150/12 × 18/5)$ kmph = 45 kmph
Question : 4
A train is running at a speed of 90 km/hr. If it crosses a signal in 10 sec., the length of the train (in metres) is
a) 324
b) 900
c) 250
d) 150
Answer »Answer: (c)
Using Rule 1,
Speed of train = 90 kmph
= $({90 × 5}/18)$ metre/second
= 25 metre/second
If the length of the train be x then,
Speed of train
= $\text"Length of train"/ \text"Time taken in crossing the signal"$
25 = $x/10$ ⇒ x = 250 metre
Question : 5
A train 100m long is running at the speed of 30 km/hr. The time (in second) in which it will pass a man standing near the railway line is :
a) 11
b) 12
c) 15
d) 10
Answer »Answer: (b)
Using Rule 1,
If a train crosses an electric pole, a sitting/standing man, km or milestone etc. then distance = Length of the train.
Then, Length of train = Speed × Time And Time = $\text"Length of train"/\text"Speed"$
and Speed = $\text"Length of train"/\text"Time"$
In this situation, the train covers it length.
Required time = $100/{30 × 1000}$ hr.
= ${100 × 60 × 60}/{30 × 1000}$ = 12 seconds
Question : 6
How many seconds will a 500 metre long train take to cross a man walking with a speed of 3 km/hr. in the direction of the moving train if the speed of the train is 63 km/hr ?
a) 30 sec
b) 40 sec
c) 45 sec
d) 25 sec
Answer »Answer: (a)
Using Rule 5,
Relative speed of train
= 63–3 = 60 kmph
= $60 × 5/18$ m / sec
Time = $\text"Length of train"/ \text"Relative Speed"$
= ${500 × 18}/{60 × 5}$ = 30 sec.
trains Shortcuts and Techniques with Examples
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Model 1 Train Vs Train in same direction
Defination & Shortcuts … -
Model 2 Train Vs Train in opposite direction
Defination & Shortcuts … -
Model 3 Train Vs Bridge/Platform
Defination & Shortcuts … -
Model 4 Train Vs Pole/Signal Post/Man
Defination & Shortcuts … -
Model 5 Train Vs Both platform and a man/a pole
Defination & Shortcuts … -
Model 6 Change in speed Vs Change with time travel
Defination & Shortcuts …
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