Model 4 Train Vs Pole/Signal Post/Man Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 6 EXERCISES

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The following question based on trains topic of quantitative aptitude

Questions : A train is running at a speed of 90 km/hr. If it crosses a signal in 10 sec., the length of the train (in metres) is

(a) 324

(b) 900

(c) 250

(d) 150

The correct answers to the above question in:

Answer: (c)

Using Rule 1,

Speed of train = 90 kmph

= $({90 × 5}/18)$ metre/second

= 25 metre/second

If the length of the train be x then,

Speed of train

= $\text"Length of train"/ \text"Time taken in crossing the signal"$

25 = $x/10$ ⇒ x = 250 metre

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Read more crossing pole signal post man Based Quantitative Aptitude Questions and Answers

Question : 1

In what time will a train 100 metres long cross an electric pole, if its speed be 144 km/hour ?

a) 5 seconds

b) 12.5 seconds

c) 3$5/4$ seconds

d) 2.5 seconds

Answer: (d)

Using Rule 1,

Speed of the train = 144 kmph

= $144 × 5/18$ = 40 m/s

When a train crosses a pole, it covers a distance equal to its own length.

The required time

= $100/40 = 5/2$ = 2.5 seconds.

Question : 2

A train, 120 m long, takes 6 seconds to pass a telegraph post; the speed of train is

a) 62 km/hr

b) 55 km/hr

c) 85 km/hr

d) 72 km/hr

Answer: (d)

Using Rule 1,

Speed of train

= $\text"Length of train"/ \text"Time taken in crossing the pole"$

= $120/6$ = 20 m/sec

= 20 × $18/5$ = 72 kmph

Question : 3

Buses start from a bus terminal with a speed of 20 km/hr at intervals of 10 minutes. What is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at intervals of 8 minutes?

a) 4 km/hr

b) 5 km/hr

c) 7 km/hr

d) 3 km/hr

Answer: (b)

Distance covered in 10 minutes at 20kmph

= distance covered in 8 minutes at (20 + x ) kmph

20 × $10/60 = 8/60 (20 + x)$

200 = 160 + 8x

8x = 40 ⇒ $x = 40/8$ = 5 kmph

Question : 4

A train 100m long is running at the speed of 30 km/hr. The time (in second) in which it will pass a man standing near the railway line is :

a) 11

b) 12

c) 15

d) 10

Answer: (b)

Using Rule 1, 

If a train crosses an electric pole, a sitting/standing man, km or milestone etc. then distance = Length of the train.
Then, Length of train = Speed × Time And Time = $\text"Length of train"/\text"Speed"$
and Speed = $\text"Length of train"/\text"Time"$

In this situation, the train covers it length.

Required time = $100/{30 × 1000}$ hr.

= ${100 × 60 × 60}/{30 × 1000}$ = 12 seconds

Question : 5

How many seconds will a 500 metre long train take to cross a man walking with a speed of 3 km/hr. in the direction of the moving train if the speed of the train is 63 km/hr ?

a) 30 sec

b) 40 sec

c) 45 sec

d) 25 sec

Answer: (a)

Using Rule 5,

Relative speed of train

= 63–3 = 60 kmph

= $60 × 5/18$ m / sec

Time = $\text"Length of train"/ \text"Relative Speed"$

= ${500 × 18}/{60 × 5}$ = 30 sec.

Question : 6

A train is 250m long. If the train takes 50 seconds to cross a tree by the railway line, then the speed of the train in km/hr is :

a) 9

b) 5

c) 18

d) 10

Answer: (c)

Using Rule 1,

Speed of train = $\text"Length of train"/ \text"Time taken in crossing"$

= $250/50$ = 5 m/sec.

= $(5 × 18/5)$ kmph = 18 kmph

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