type 1 basic simple interest using formula Section-Wise Topic Notes With Detailed Explanation And Example Questions

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The following question based on simple interest topic of quantitative aptitude

Questions : A money lender finds that due to fall in the annual rate of interest 8% to 7$3/4$% , his yearly income diminishes by Rs.61.50. His capital is

(a) Rs.23800

(b) Rs.22400

(c) Rs.26000

(d) Rs.24600

The correct answers to the above question in:

Answer: (d)

Difference in rate

= $(8 - 7{3}/4)% = 1/4$%

Let the capital be Rs.x.

$1/4$% of x = 61.50

x = 61.50 × 100 × 4 = Rs.24600

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Read more basic problems using formula Based Quantitative Aptitude Questions and Answers

Question : 1

What sum of money must be given as simple interest for six months at 4% per annum in order to earn Rs.150 interest?

a) Rs.7500

b) Rs.5000

c) Rs.15000

d) Rs.10000

Answer: (a)

Using Rule 1
Simple Interest (S.I.)= ${\text"Principal × Rate × Time"/100$ or
S.I. = ${\text"P × R × T"/100$
P = ${\text"S.I." × 100}/\text"R × T"$, R = ${\text"S.I." × 100}/\text"P × T"$, T = ${\text"S.I." × 100}/\text"P × R"$
A = P + S.I. or S.I. = A - P

P = ${150 × 100}/4 × 2/1$ = Rs.7500

Question : 2

A sum of money amounts to Rs.5,200 in 5 years and to Rs.5,680 in 7 years at simple interest. The rate of interest per annum is

a) 4%

b) 3%

c) 6%

d) 5%

Answer: (c)

P + S.I. for 5 years = 5200 ..(i)

P + SI for 7 years = 5680 ...(ii)

On subtracting equation (i) from (ii),

SI for 2 years = 480

SI for 1 year = Rs.240

From equation (i),

P + 5 × 240 = 5200

P = 5200 - 1200 = Rs.4000

R = ${SI × 100}/{T × P}$

= ${240 × 100}/{1 × 4000}$ = 6%

Using Rule 12
If certain sum P amounts to Rs. $A_1$ in $t_1$ years at rate of R% and the same sum amounts to Rs. $A_2$ in $t_2$ years at same rate of interest R%. Then,
(i) R = $({A_1 - A_2}/{A_2T_1 - A_1T_2})$ × 100
(ii) P = $({A_2T_1 - A_1T_2}/{T_1 - T_2})$

R = $({A_1 - A_2}/{A_2T_1 - A_1T_2})$ × 100

= $({5200 - 5680}/{5680 × 5 - 5200 × 7}) × 100$

= ${- 480}/{28400 - 36400}$ × 100

= ${- 480}/{- 8000} × 100$ = 6%

Question : 3

A sum of money lent out at simple interest amounts to Rs.720 after 2 years and to Rs.1020 after a further period of 5 years. The sum is :

a) Rs.600

b) Rs.500

c) Rs.710

d) Rs.700

Answer: (a)

Principal + SI for 2 years = Rs.720 .... (i)

Principal + SI for 7 years = Rs.1020 .....(ii)

Subtracting equation (i) from (ii) get,

SI for 5 years

= Rs.(1020 - 720) = Rs.300

SI for 2 years

= Rs.300 × $2/5$ = Rs.120

Principal = Rs.(720 - 120) = Rs.600

Using Rule 12,

P = $({A_2T_1 - A_1T_2}/{T_1 - T_2})$

= $({1020 × 2 - 720 × 7}/{2 - 7})$

= $({2040 - 5040}/{- 5})$

= ${- 3000}/{- 5}$ = Rs.600

Question : 4

Rs.800 becomes Rs.956 in 3 years at a certain rate of simple interest. If the rate of interest is increased by 4%, what amount will 800 become in 3 years ?

a) Rs.1025

b) Rs.1020.80

c) Rs.1050

d) Rs.1052

Answer: (d)

Using Rule 1,

S.I. = 956 - 800 = Rs.156

Rate = ${S.I. × 100}/{Principal × Time}$

= ${156 × 100}/{800 × 3}$ = 6.5% per annum

New rate = 10.5%

S.I. = ${\text"Principal × Rate × Time"/100$

= ${800 × 3 × 10.5}/100$ = Rs.252

Amount = 800 + 252 = Rs.1052

Question : 5

The sum of money, that will give Rs.1 as interest per day at the rate of 5% per annum simple interest is

a) Rs.36500

b) Rs.3650

c) Rs.7300

d) Rs.730

Answer: (c)

Using Rule 1,

The sum of money will give Rs.365 as simple interest in a year.

S.I. = $\text"PRT"/100$

365 = ${P × 5 × 1}/100$

P = ${365 × 100}/5$ = Rs.7300

Question : 6

In what time will Rs.72 become Rs.81 at 6$1/4$% per annum simple interest ?

a) 3 years

b) 2 years

c) None of these

d) 2 years 6 months

Answer: (b)

Using Rule 1,

Interest = Rs.(81–72)= Rs.9

Let the time be t years.

Then, 9 = ${72 × 25 × t}/{4 × 100}$

t = ${9 × 400}/{72 × 25}$ = 2 years.

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