Model 1 Basic Time & Distance using formula Section-Wise Topic Notes With Detailed Explanation And Example Questions

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The following question based on time & distance topic of quantitative aptitude

Questions : An aeroplane covers a certain distance at a speed of 240 km hour in 5 hours. To cover the same distance in 1$2/3$ hours, it must travel at a speed of :

(a) 720 km./hr.

(b) 600 km./hr.

(c) 360 km./hr.

(d) 300 km./hr.

The correct answers to the above question in:

Answer: (a)

Using Rule 1,

Let the required speed is x km/ hr

Then, $240 × 5 = 5/3 × x$

x = 720 km/hr.

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Read more basic problems formulas Based Quantitative Aptitude Questions and Answers

Question : 1

The speed of a bus is 72 km/hr. The distance covered by the bus in 5 seconds is

a) 74.5 m

b) 50 m

c) 60 m

d) 100 m

Answer: (d)

Using Rule 1,

Speed of bus = 72 kmph

= $({72 × 5}/18)$ metre/second

= 20 metre/second

∴ Required distance

= 20 × 5 = 100 metre

Question : 2

A train is moving with the speed of 180 km/hr. Its speed (in metres per second) is :

a) 50

b) 30

c) 40

d) 5

Answer: (a)

Using Rule 1,

Speed = 180 kmph

= ${180 × 5}/18$ m/sec = 50 m/sec

[Since, 1 km/hr = $5/18$ m/s]

Question : 3

A train covers a distance of 10 km in 12 minutes. If its speed is decreased by 5 km/hr, the time taken by it to cover the same distance will be :

a) 11 minutes 20 sec

b) 13 minutes

c) 13 minutes 20 sec

d) 10 minutes

Answer: (b)

Using Rule 1,

Speed of train = $\text"Distance"/ \text"Time"$

= $10/{12/60}$ kmph = ${10 × 60}/12 = 50$ kmph

New speed = 45 kmph

Required time = $10/45$ hour

= $2/9 × 60$ minutes = $40/3$ minutes

= 13 minutes 20 seconds

Question : 4

The speed 3$1/3$ m/sec when expressed in km/hour becomes

a) 12

b) 10

c) 9

d) 8

Answer: (a)

Since, 1 m/sec = $18/5$ kmph

$10/3$ m/sec

= $18/5 × 10/3$ = 12 kmph

Question : 5

A man crosses a road 250 metres wide in 75 seconds. His speed in km/hr is :

a) 15

b) 12.5

c) 12

d) 10

Answer: (b)

Using Rule 1,

Speed = $\text"Distance"/\text"Time" = 250/75$

= $10/3$ m/sec = $10/3 × 18/5$ km/hr

[Since, 1 m/s = $18/5$ km/hr]

= 2 × 6 km/hr. = 12 km/hr.

Question : 6

A man walks 'a' km in 'b' hours. The time taken to walk 200 metres is

a) ${ab}/200$ hours

b) $b/a$ hours

c) $b/{5a}$ hours

d) ${200b}/a$ hours

Answer: (b)

Using Rule 1,

Man's speed = $\text"Distance"/ \text"Time"$

= $a/b$ kmph = ${1000a}/b$ m/hour

Time taken in walking 200 metre

= $200/{{1000a}/b} =b/{5a}$ hours

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