Model 1 Basic Time & Distance using formula Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 5 EXERCISES
The following question based on time & distance topic of quantitative aptitude
(a) 12
(b) 10
(c) 9
(d) 8
The correct answers to the above question in:
Answer: (a)
Since, 1 m/sec = $18/5$ kmph
$10/3$ m/sec
= $18/5 × 10/3$ = 12 kmph
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Read more basic problems formulas Based Quantitative Aptitude Questions and Answers
Question : 1
An aeroplane covers a certain distance at a speed of 240 km hour in 5 hours. To cover the same distance in 1$2/3$ hours, it must travel at a speed of :
a) 720 km./hr.
b) 600 km./hr.
c) 360 km./hr.
d) 300 km./hr.
Answer »Answer: (a)
Using Rule 1,
Let the required speed is x km/ hr
Then, $240 × 5 = 5/3 × x$
x = 720 km/hr.
Question : 2
The speed of a bus is 72 km/hr. The distance covered by the bus in 5 seconds is
a) 74.5 m
b) 50 m
c) 60 m
d) 100 m
Answer »Answer: (d)
Using Rule 1,
Speed of bus = 72 kmph
= $({72 × 5}/18)$ metre/second
= 20 metre/second
∴ Required distance
= 20 × 5 = 100 metre
Question : 3
A train is moving with the speed of 180 km/hr. Its speed (in metres per second) is :
a) 50
b) 30
c) 40
d) 5
Answer »Answer: (a)
Using Rule 1,
Speed = 180 kmph
= ${180 × 5}/18$ m/sec = 50 m/sec
[Since, 1 km/hr = $5/18$ m/s]
Question : 4
A man crosses a road 250 metres wide in 75 seconds. His speed in km/hr is :
a) 15
b) 12.5
c) 12
d) 10
Answer »Answer: (b)
Using Rule 1,
Speed = $\text"Distance"/\text"Time" = 250/75$
= $10/3$ m/sec = $10/3 × 18/5$ km/hr
[Since, 1 m/s = $18/5$ km/hr]
= 2 × 6 km/hr. = 12 km/hr.
Question : 5
A man walks 'a' km in 'b' hours. The time taken to walk 200 metres is
a) ${ab}/200$ hours
b) $b/a$ hours
c) $b/{5a}$ hours
d) ${200b}/a$ hours
Answer »Answer: (b)
Using Rule 1,
Man's speed = $\text"Distance"/ \text"Time"$
= $a/b$ kmph = ${1000a}/b$ m/hour
Time taken in walking 200 metre
= $200/{{1000a}/b} =b/{5a}$ hours
Question : 6
A bullock cart has to cover a distance of 120 km. in 15 hours. If it covers half of the journey in $3/5$th time, the speed to cover the remaining distance in the time left has to be
a) 15 km/hr
b) 10 km/hr
c) 6.67 km/hr
d) 6.4 km/hr
Answer »Answer: (c)
Using Rule 1,
Remaining time
= $2/5 × 15 = 6$ hours
Required speed
= $60/6$ = 10 kmph
GET time & distance PRACTICE TEST EXERCISES
Model 1 Basic Time & Distance using formula
Model 2 Vehicles in x/y of its usual speed
Model 3 Problems on average speed
Model 4 Time & Distance with Ratios
Model 5 Problems with Races
time & distance Shortcuts and Techniques with Examples
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Model 1 Basic Time & Distance using formula
Defination & Shortcuts … -
Model 2 Vehicles in x/y of its usual speed
Defination & Shortcuts … -
Model 3 Problems on average speed
Defination & Shortcuts … -
Model 4 Time & Distance with Ratios
Defination & Shortcuts … -
Model 5 Problems with Races
Defination & Shortcuts …
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