Model 1 Basic Time & Distance using formula Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 5 EXERCISES
The following question based on time & distance topic of quantitative aptitude
(a) 15.5 m/sec.
(b) 12 m/sec.
(c) l0 m/sec.
(d) 8.5 m/sec.
The correct answers to the above question in:
Answer: (d)
30.6 kmph = $(30.6 × 5/18)$ m/sec.
= 8.5 m/sec
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Read more basic problems formulas Based Quantitative Aptitude Questions and Answers
Question : 1
A boy runs 20 km in 2.5 hours. How long will he take to run 32 km at double the previous speed ?
a) 5 hours
b) 4$1/2$ hours
c) 2$1/2$ hours
d) 2 hours
Answer »Answer: (d)
Using Rule 1,
The boy covers 20 km in 2.5 hours.
Speed = $20/{2.5}$ = 8 km/hr.
New speed = 16 km/hr
Time = $32/16$ = 2 hours.
Question : 2
A car travelling at a speed of 40 km/hour can complete a journey in 9 hours. How long will it take to travel the same distance at 60 km/hour ?
a) 4$1/2$ hours
b) 4 hours
c) 3 hours
d) 6 hours
Answer »Answer: (d)
Total distance covered
= Speed × Time
= 40 × 9 = 360 km.
The required time at 60 kmph
= $360/60 = 6$ hours.
Using Rule 9,Speed(s) ∝ $1/{time (t)}$ ⇒ s ∝ $1/t$$s_1t_1 = s_2t_2$(Provided distance is constant)
Here, $S_1 = 40, t_1 = 9, S_2 = 60, t_2$ = ?
$S_1t_1 = S_2t_2$
40 × 9 = 60 × $t_2$
$t_2 = {4 × 9}/6$ = 6 hours
Question : 3
Walking at the rate of 4 km an hour, a man covers a certain distance in 3 hours 45 minutes. If he covers the same distance on cycle, cycling at the rate of 16·5 km/hour, the time taken by him is
a) 45.55 minutes
b) 55.44 minutes
c) 54.55 minutes
d) 55.45 minutes
Answer »Answer: (b)
Using Rule 1,
Distance covered on foot
= 4 × 3$3/4$ km. = 15 km.
Time taken on cycle
= $\text"Distance"/\text"Speed" = 15/{16.5}$ hour
= ${15 × 60}/{16.5}$ minutes
= 54.55 minutes
Question : 4
Sarita and Julie start walking from the same place in the opposite directions. If Julie walks at a speed of 2$1/2$ km/hr and Sarita at a speed of 2 km/hr, in how much time will they be 18 km apart ?
a) 4.8 hrs
b) 5.0 hrs
c) 4.5 hrs
d) 4.0 hrs
Answer »Answer: (d)
Using Rule 12,If both objects run in opposite direction then, Relative speed = Sum of speeds.If both objects run in the same direction then, Relative speed = Difference of Speeds.Time taken in meeting = $\text"Distance between them"/\text"Relative Speed"$
Relative speed
=$(5/2 + 2)$ kmph = $9/2$ kmph
Time = $\text"Distance"/ \text"Relative speed"$
=$18/{9/2} = {18 × 2}/9$ = 4 hours
Question : 5
You arrive at your school 5 minutes late if you walk with a speed of 4 km/h, but you arrive 10 minutes before the scheduled time if you walk with a speed of 5 km/h. The distance of your school from your house (in km) is
a) 2
b) 10
c) 5
d) 4
Answer »Answer: (b)
If the required distance be = x km, then
$x/4 - x/5 = {10 + 5}/60$
${5x - 4x}/20 = 1/4$
$x/20 = 1/4 ⇒ x= 1/4 × 20$ = 5 km.
Using Rule 10,If a man travels at the speed of $s_1$, he reaches his destination $t_1$ late while he reaches $t_2$ before when he travels at $s_2$ speed, then the distance between the two places is D = ${(S_1 × S_2)(t_1 + t_2)}/{S_2 - S_1}$
Here, $S_1 = 4, t_1 = 5, S_2 = 5, t_2$= 10
Distance =${(S_1 × S_2)(t_1 + t_2)}/{S_2 - S_1}$
=${(4 × 5)(5 + 10)}/{5 - 4}$
=20 × $15/60$ = 5 kms
Question : 6
A boy goes to his school from his house at a speed of 3 km/hr and returns at a speed of 2 km/ hr. If he takes 5 hours in going and coming, the distance between his house and school is :
a) 6.5 km
b) 5.5 km
c) 5 km
d) 6 km
Answer »Answer: (d)
Let the required distance be x km. Then,
$x/3 + x/2$ = 5
${2x + 3x}/6$ = 5
5x = 6 × 5
x = ${6 × 5}/5$ = 6 km
Using Rule 5,
Here, x = 3, y = 2
Average Speed = ${2 × x × y}/{x + y}$
= ${2 × 3 × 2}/{3 + 2} = 12/5$ km/hr
Total distance = $12/5 × 5$ = 12km
Required distance = $12/2$ = 6 km
GET time & distance PRACTICE TEST EXERCISES
Model 1 Basic Time & Distance using formula
Model 2 Vehicles in x/y of its usual speed
Model 3 Problems on average speed
Model 4 Time & Distance with Ratios
Model 5 Problems with Races
time & distance Shortcuts and Techniques with Examples
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Model 1 Basic Time & Distance using formula
Defination & Shortcuts … -
Model 2 Vehicles in x/y of its usual speed
Defination & Shortcuts … -
Model 3 Problems on average speed
Defination & Shortcuts … -
Model 4 Time & Distance with Ratios
Defination & Shortcuts … -
Model 5 Problems with Races
Defination & Shortcuts …
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