model 1 profit x after discount y Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 4 EXERCISES
The following question based on discount topic of quantitative aptitude
(a) 20%
(b) 20.5%
(c) 18%
(d) 18.5%
The correct answers to the above question in:
Answer: (a)
If the CP of radio be x, then
$108/100 of x = {480 × 90}/100$
${x × 108}/100$ = 432
$x = {432 × 100}/108$ = Rs.400
Gain per cent (if no discount is allowed)
= $80/400 × 100$ = 20%
Using Rule 6,
Here, r = 8%, D = 10%, M.P. = Rs.480
$\text"MP"/\text"CP" = {100 + r}/{100 - D}$
$480/\text"CP" = {100 + 8}/{100 - 10}$
C.P. = ${480 × 90}/108$ = Rs.400
Gain % = $\text"S.P. - C.P."/\text"C.P." × 100$
(without discount)
= ${480 - 400}/400 × 100$
= $80/400 × 100$ = 20%
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Read more based problems makes profit Based Quantitative Aptitude Questions and Answers
Question : 1
How much percent above the cost price should a shopkeeper mark his goods so as to earn a profit of 32% after allowing a discount of 12% on the marked price ?
a) 45%
b) 60%
c) 50%
d) 40%
Answer »Answer: (c)
Let the C.P. be 100 and the marked price be x.
$x × 88/100$ = 132
$x = {132 × 100}/88$ = 150
i.e., more by 50%
Using Rule 9,The marked price of an article is fixed in such a way that after allowing a discount of r% a profit of R% is obtained. Then the marked price of the article is $({r + R}/{100 - r} × 100)$% more than its cost price.
Here, r = 12% R = 32%
Required percentage
= $({r + R}/{100 - r} × 100)$%
= $({12 × 32}/{100 - 12}) × 100%$
= $44/88 × 100$ = 50%
Question : 2
A tradesman marks his goods at such a price that after allowing a discount of 15%, he makes a profit of 20%. What is the marked price of an article whose cost price is Rs.170 ?
a) Rs.200
b) Rs.220
c) Rs.240
d) Rs.260
Answer »Answer: (c)
If the marked price be x, then
$x × 85/100 = {170 × 120}/100$
x × 85 = 170 × 120
$x = {170 × 120}/85$ = Rs.240
Using Rule 6,
Here, D = 15% r = 20%
C.P. = Rs.170
$\text"MP"/\text"CP" = {100 + r}/{100 - D}$
$\text"MP"/170 = {100 + 20}/{100 - 15}$
$\text"M.P."/170 = 120/85$
M.P. = ${120 × 170}/85$
M.P. = Rs.240
Question : 3
The marked price of an electric iron is Rs.300. The shopkeeper allows a discount of 12% and still gains 10%. If no discount is allowed, his gain per cent would have been :
a) 30%
b) 27%
c) 20%
d) 25%
Answer »Answer: (d)
SP of electric iron
= 88% of 300
= Rs.${300 × 88}/100$ = Rs.264
Profit = 10%
CP of electric iron
= $100/110 × 264$ = Rs.240
After no discount,
Gain = 300 - 240 = Rs.60
Gain per cent
= $60/240$ × 100 = 25%
Using Rule 6,
Here, M.P. = Rs.300, r = 10%, D = 12%.
$\text"MP"/\text"CP" = {100 + r}/{100 - D}$
$300/\text"CP" = {100 + 10}/{100 - 12}$
C.P. = ${300 × 88}/110$
Gain % (without discount)
= ${300 - 240}/240 × 100$ = 25%
Question : 4
A shopkeeper earns a profit of 10% after allowing a discount of 20% on the marked price. The cost price of the article whose marked price is Rs.880, is
a) Rs.680
b) Rs.774
c) Rs.704
d) Rs.640
Answer »Answer: (d)
SP of article
= (100 - 20)% of 880
= 80%of 880
= 880 × $80/100$ = Rs.704
Let CP be x
Again, 110% of x = 704
x = $704/110 × 100$ = Rs.640
Original cost = Rs.640
Using Rule 6,
Here, r = 10%, D = 20%, M.P. = Rs.880, C.P. = ?
$\text"MP"/\text"CP" = {100 + r}/{100 - D}$
$880/\text"C.P." = {100 + 10}/{100 - 20}$
C.P. = ${880 × 80}/110$
C.P. = Rs.640
GET discount PRACTICE TEST EXERCISES
model 1 profit x after discount y
model 2 hiking & discounting
model 3 successive discount
model 4 mixed discount problems of marked price
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