model 1 profit x after discount y Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 4 EXERCISES

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The following question based on discount topic of quantitative aptitude

Questions : Marked price of an article is Rs.275. Shopkeeper allows a discount of 5% and he gets a profit of 4.5%. The actual cost of the article is

(a) Rs.210

(b) Rs.215

(c) Rs.250

(d) Rs.225

The correct answers to the above question in:

Answer: (c)

Let C.P. of article be x

${x × 104.5}/100 = {275 × 95}/100$

x × 104.5 = 275 × 95

$x = {275 × 95}/{104.5}$ = Rs.250

Using Rule 6,

M.P. = Rs.275, D = 5%,

r = 4.5%, C.P. = ?

$\text"MP"/\text"CP" = {100 + r}/{100 - D}$

$275/\text"C.P." = {100 + 4.5}/{100 - 5}$

C.P. = ${275 × 95}/{104.5}$

C.P. = Rs.250

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Read more based problems makes profit Based Quantitative Aptitude Questions and Answers

Question : 1

After allowing a discount of 16%, there was still a gain of 5%. Then the percentage of marked price over the cost price is

a) 25%

b) 21%

c) 15%

d) 18%

Answer: (a)

Let the C.P. of article be Rs.100 and its marked price be x.

$x × 84/100 = 105$

$x = {105 × 100}/84 = 125$

Required percentage = 25%

Using Rule 6,

Here, r = 5% D = 16%

$\text"MP"/\text"CP" = {100 + r}/{100 - D}$

= ${100 + 5}/{100 - 16} = 105/84$

Required Percentage

= ${105 - 84}/84 × 100$ = 25%

Question : 2

A shopkeeper earns a profit of 10% after allowing a discount of 20% on the marked price. The cost price of the article whose marked price is Rs.880, is

a) Rs.680

b) Rs.774

c) Rs.704

d) Rs.640

Answer: (d)

SP of article

= (100 - 20)% of 880

= 80%of 880

= 880 × $80/100$ = Rs.704

Let CP be x

Again, 110% of x = 704

x = $704/110 × 100$ = Rs.640

Original cost = Rs.640

Using Rule 6,

Here, r = 10%, D = 20%, M.P. = Rs.880, C.P. = ?

$\text"MP"/\text"CP" = {100 + r}/{100 - D}$

$880/\text"C.P." = {100 + 10}/{100 - 20}$

C.P. = ${880 × 80}/110$

C.P. = Rs.640

Question : 3

The marked price of an electric iron is Rs.300. The shopkeeper allows a discount of 12% and still gains 10%. If no discount is allowed, his gain per cent would have been :

a) 30%

b) 27%

c) 20%

d) 25%

Answer: (d)

SP of electric iron

= 88% of 300

= Rs.${300 × 88}/100$ = Rs.264

Profit = 10%

CP of electric iron

= $100/110 × 264$ = Rs.240

After no discount,

Gain = 300 - 240 = Rs.60

Gain per cent

= $60/240$ × 100 = 25%

Using Rule 6,

Here, M.P. = Rs.300, r = 10%, D = 12%.

$\text"MP"/\text"CP" = {100 + r}/{100 - D}$

$300/\text"CP" = {100 + 10}/{100 - 12}$

C.P. = ${300 × 88}/110$

Gain % (without discount)

= ${300 - 240}/240 × 100$ = 25%

Question : 4

A trader allows a trade discount of 20% and a cash discount of 6$1/4$% on the marked price of the goods and gets a net gain of 20% of the cost. By how much above the cost should the goods be marked for the sale ?

a) 70%

b) 60%

c) 40%

d) 50%

Answer: (b)

Let C.P. of article = Rs.100

Marked price = x

Single equivalent discount

= $(20 + {25/4} - {20 × 25}/400)$% = 25%

$x × 75/100$ = 120

$x = {120 × 100}/75$ = Rs.160

160 - 100 = 60%

Question : 5

A dealer offers a discount of 10% on the marked price of an article and still makes a profit of 20%. If its marked price is Rs.800, then the cost price of the article is :

a) Rs.600

b) Rs.700

c) Rs.900

d) Rs.800

Answer: (a)

S.P. of that article

= 800 × $90/100$ = Rs.720

He still makes 20% profit

C.P. of the article

= 720 $×100/120$ = Rs.600

Using Rule 6,
If r% of profit or loss occur after giving D% discount on marked price, then
$\text"MP"/\text"CP" = {100 ± r}/{100 - D}$
(positive sign for profit and negative for loss)

Here, r = 20%, D = 10%, M.P. = Rs.800, C.P. = ?

$\text"MP"/\text"CP" = {100 + r}/{100 - D}$

$800/\text"CP" = {100 + 20}/{100 - 10}$

C.P. = ${800 × 90}/120$

C.P. = Rs.600

Question : 6

A grinder was marked at Rs.3,600. After given a discount of 10% the dealer made a profit of 8%. Calculate the cost price.

a) Rs.2,960

b) Rs.3,240

c) Rs.3,000

d) Rs.3,312

Answer: (c)

If the C.P. of grinder be x, then

${x × 108}/100 = {3600 × 90}/100$ = 3240

$x = {3240 × 100}/108$ = Rs.3000

Using Rule 6,

M.P. = Rs.3600, D = 10%,

r = 8%, C.P. = ?

$\text"MP"/\text"CP" = {100 + r}/{100 - D}$

$3600/\text"CP" = {100 + 8}/{100 - 10}$

C.P. = ${3600 × 90}/108$

= ${3600 × 10}/12$ = Rs.3000

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