model 1 profit x after discount y Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 4 EXERCISES

Top 10,000+ Aptitude Memory Based Exercises

The following question based on discount topic of quantitative aptitude

Questions : A manufacturer marked an article at Rs.50 and sold it allowing 20% discount. If his profit was 25%, then the cost price of the article was

(a) Rs.30

(b) Rs.32

(c) Rs.40

(d) Rs.35

The correct answers to the above question in:

Answer: (b)

Marked price = Rs.50

S.P. after discount = 80% of 50 = Rs.40

If the CP of article be x, then

${125 × x}/100 = 40$

$x = {40 × 100}/125$ = Rs.32

Using Rule 6,

Here, M.P. = Rs.50, C.P. = ?,

r = 25%, D = 20%

$\text"MP"/\text"CP" = {100 + r}/{100 - D}$

$50/\text"CP" = {100 + 25}/{100 - 20}$

C.P.= ${50 × 80}/125$ = Rs.32

Practice discount (model 1 profit x after discount y) Online Quiz

Discuss Form

Valid first name is required.
Please enter a valid email address.
Your genuine comment will be useful for all users! Each and every comment will be uploaded to the question after approval.

Read more based problems makes profit Based Quantitative Aptitude Questions and Answers

Question : 1

A shopkeeper marks his goods 40% above the cost price. He allows a discount of 5% for cash payment to his customers. He receives Rs.1064 after paying the discount. His profit is

a) Rs.800

b) Rs.200

c) Rs.264

d) Rs.164

Answer: (a)

Cost price of article = Rs.x

$x × 140/100 × 95/100 = 1064$

$x = {1064 × 100 × 100}/{140 × 95}$ = Rs.800

Question : 2

A grinder was marked at Rs.3,600. After given a discount of 10% the dealer made a profit of 8%. Calculate the cost price.

a) Rs.2,960

b) Rs.3,240

c) Rs.3,000

d) Rs.3,312

Answer: (c)

If the C.P. of grinder be x, then

${x × 108}/100 = {3600 × 90}/100$ = 3240

$x = {3240 × 100}/108$ = Rs.3000

Using Rule 6,

M.P. = Rs.3600, D = 10%,

r = 8%, C.P. = ?

$\text"MP"/\text"CP" = {100 + r}/{100 - D}$

$3600/\text"CP" = {100 + 8}/{100 - 10}$

C.P. = ${3600 × 90}/108$

= ${3600 × 10}/12$ = Rs.3000

Question : 3

A dealer offers a discount of 10% on the marked price of an article and still makes a profit of 20%. If its marked price is Rs.800, then the cost price of the article is :

a) Rs.600

b) Rs.700

c) Rs.900

d) Rs.800

Answer: (a)

S.P. of that article

= 800 × $90/100$ = Rs.720

He still makes 20% profit

C.P. of the article

= 720 $×100/120$ = Rs.600

Using Rule 6,
If r% of profit or loss occur after giving D% discount on marked price, then
$\text"MP"/\text"CP" = {100 ± r}/{100 - D}$
(positive sign for profit and negative for loss)

Here, r = 20%, D = 10%, M.P. = Rs.800, C.P. = ?

$\text"MP"/\text"CP" = {100 + r}/{100 - D}$

$800/\text"CP" = {100 + 20}/{100 - 10}$

C.P. = ${800 × 90}/120$

C.P. = Rs.600

Question : 4

In order to maintain the price line a trader allows a discount of 10% on the marked price of an article. However, he still makes a profit of 17% on the cost price. Had he sold the article at the marked price, he would have earned a profit per cent of

a) 35%

b) 33%

c) 30%

d) 32%

Answer: (c)

Let the marked price be Rs.100.

S.P. = 90% of 100 = Rs.90

Profit = 17%

C.P. = Rs.$90 × 100/117$ = Rs.$1000/13$

If no discount is allowed,

S.P. = Rs.100

Profit = Rs.$(100 - 1000/13)$ = Rs.$300/13$

Profit % = ${300/13}/{1000/13}$ × 100 = 30%

Using Rule 6,

Here, D = 10%, r = 17%,

Let the M.P. = Rs.100

$\text"MP"/\text"CP" = {100 + r}/{100 - D}$

$100/\text"CP" = {100 + 17}/{100 - 10}$

$100/\text"C.P." = 117/90$

C.P. = ${100 × 90}/117 = 1000/13$

Profit = S.P. - C.P.

= $100 - 1000/13$ = Rs.$300/13$

Profit % = ${300/13}/{1000/13} × 100%$ = 30%

Question : 5

The price that Akbar should mark on a pair of shoes which costs him Rs.1,200 to gain 12% after allowing a discount of 16% (in rupees) is

a) 1,500

b) 1,600

c) 1,344

d) 1,433

Answer: (b)

Let the marked price be x.

$x × 84/100 = {1200 × 112}/100$

$x × 84/100 = 112 × 12$

$x = {112 × 1200}/84$ = Rs.1600

Using Rule 6,

C.P. = Rs.1200, r = 12%, D = 16%

$\text"MP"/\text"CP" = {100 + r}/{100 - D}$

$\text"MP"/1200 = {100 + 12}/{100 - 16}$

M.P.= ${112 × 1200}/84$ = Rs.1600

Question : 6

A shopkeeper offers 10% discount on the marked price of his articles and still makes a profit of 20%. What is the actual cost of the article marked Rs.500 for him ?

a) Rs.375

b) Rs.400

c) Rs.440

d) Rs.425

Answer: (a)

Let the cost price of article be x

$500 × 90/100 = 120/100 × x$

450 = ${6x}/5$

$x = {450 × 5}/6$ = Rs.375

Using Rule 6,

C.P. = ? , M.P. = Rs.500, r = 20%, D = 10%

$\text"MP"/\text"CP" = {100 + r}/{100 - D}$

$500/\text"CP" = {100 + 20}/{100 - 10}$

C.P.= ${500 × 90}/120$ = Rs.375

Recently Added Subject & Categories For All Competitive Exams

New 100+ Compound Interest MCQ with Answers PDF for IBPS

Compound Interest verbal ability questions and answers solutions with PDF for IBPS RRB PO. Aptitude Objective MCQ Practice Exercises all competitive exams

02-Jul-2024 by Careericons

Continue Reading »

100+ Mixture and Alligation MCQ Questions PDF for IBPS

Most importantly Mixture and Alligation multiple choice questions and answers with PDF for IBPS RRB PO. Aptitude MCQ Practice Exercises all Bank Exams

02-Jul-2024 by Careericons

Continue Reading »

IBPS Profit and Loss Questions Solved Problems with PDF

Most important Profit and Loss multiple choice questions and answers with PDF for IBPS RRB PO. 100+ Aptitude MCQ Practice Exercises all competitive exams

28-Jun-2024 by Careericons

Continue Reading »

100+ Average Aptitude Questions Answers solutions MCQ PDF

New Average multiple choice questions and answers with PDF for IBPS RRB PO. 100+ Quantitative Aptitude MCQ Practice Exercises all competitive exams

28-Jun-2024 by Careericons

Continue Reading »