model 1 profit x after discount y Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 4 EXERCISES
The following question based on discount topic of quantitative aptitude
(a) 35%
(b) 34$2/3$%
(c) 30%
(d) 33$1/3$%
The correct answers to the above question in:
Answer: (d)
Let the CP be Rs.100.
Then SP = Rs.120
Let the marked price be x.
Then, 90% of x = Rs.120
$x = {120 × 100}/90$
= $400/3 = 133{1}/3$
It is $33{1}/3$% higher than the CP.
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Read more based problems makes profit Based Quantitative Aptitude Questions and Answers
Question : 1
By giving a discount of 10% on the marked price of Rs.1100 of a cycle, a dealer gains 10%. The cost price of the cycle is :
a) Rs.891
b) Rs.1089
c) Rs.1100
d) Rs.900
Answer »Answer: (d)
Selling Price
= Rs.(1100 - 10% of 1100)
= Rs.(1100 - 110) = Rs.990
Let the cost price = x
x + 10% of x = 990
${11x}/10$ = 990
$x = {990 × 10}/11$ = Rs.900
Using Rule 6,
Here, r = 10%, D = 10%, M.P. = Rs.1100, C.P. = ?
$\text"MP"/\text"CP" = {100 + r}/{100 - D}$
$1100/\text"CP" = {100 + 10}/{100 - 10}$
C.P. = ${1100 × 90}/110$ = Rs.900
Question : 2
The marked price of an article is Rs.200. A discount of 12$1/2$%is allowed on the marked price and a profit of 25% is made. The cost price of the article is :
a) Rs.140
b) Rs.120
c) Rs.200
d) Rs.175
Answer »Answer: (a)
Discount = $12{1}/2% = 25/2$%
After discount S.P.
= Rs.200 × 87.5 = Rs.175
Gain % = 25%
Required C.P.
= Rs.$100/125$ × 175 = Rs.140
Using Rule 6,
Here, r = 25%, D = 12.5%,M.P. = Rs.200, C.P. = ?
$\text"MP"/\text"CP" = {100 + r}/{100 - D}$
$200/\text"CP" = {100 + 25}/{100 - 12.5}$
C.P. = ${200 × 87.5}/125$ ⇒ C.P.= Rs.140
Question : 3
A profit of l0% is made after giving a discount of 5% on a T. V. If the marked price of the TV is Rs.2640.00, the cost price of the TV was :
a) Rs.2396
b) Rs.2380
c) Rs.2280
d) Rs.2296
Answer »Answer: (c)
Let the C.P. of TV be x, then
${x × 110}/100 = 2640 × 95/100$
$x = {2640 × 95}/110$ = Rs.2280
Using Rule 6,
Here, r = 10%, D = 5%,
M.P. = Rs.264000,C.P. = ?
$\text"MP"/\text"CP" = {100 + r}/{100 - D}$
$2640/\text"CP" = {100 + 10}/{100 - 5}$
C.P. = ${2640 × 95}/110$
= 24 × 95 = 2280
Question : 4
A shopkeeper earns a profit of 12% on selling a book at 10% discount on the printed price. The ratio of the cost price and the printed price of the book is
a) 47 : 51
b) 47 : 56
c) 45 : 56
d) 45 : 51
Answer »Answer: (c)
Let the CP be Rs.100.
SP = Rs.112
If the marked price be x, then
90 % of x = 112
x = ${112 × 100}/90$ = Rs.$1120/9$
Required ratio = 100 : $1120/9$
= 900 : 1120 = 45 : 56
Using Rule 6,
Here, r = 12% D = 10%
$\text"MP"/\text"CP" = {100 + r}/{100 - D}$
$\text"MP"/\text"CP" = {100 + 12}/{100 - 10}$
$\text"MP"/\text"CP" = 112/90$
$\text"CP"/\text"MP" = 90/112$
$\text"CP"/\text"MP" = 45/56$
C.P. : M.P. = 45 : 56
Question : 5
After allowing a discount of 12% on the marked price, a shopkeeper still gains 21%. The marked price is above the cost price by
a) 42.5%
b) 37.5%
c) 25%
d) 30%
Answer »Answer: (b)
C.P. of article = Rs.100
Marked price be x
${x × 88}/100$ = 121
$x = {121 × 100}/88$ = Rs.137.5
i.e. 37.5% above C.P.
Using Rule 9,
Here, r = 12%, R = 21%
Required percentage
= $({r + R}/{100 - r} × 100)$%
= $({12 + 21}/{100 - 12}) × 100%$
= $33/88 × 100%$
= $3/8 × 100$
= $300/8$% = 37.5%
Question : 6
The true discount on Rs.1, 860 due after a certain time at 5% is Rs.60. Find the time after which it is due.
a) 1 year
b) 9 months
c) 10 months
d) 8 months
Answer »Answer: (d)
Present worth
= 1860 - 60 = Rs.1800
Time = ${100 × \text"True Discount"}/\text"Present worth × Rate"$
= ${100 × 60}/{1800 × 5} = 2/3$ year
= $(2/3 × 12)$ months = 8 months
GET discount PRACTICE TEST EXERCISES
model 1 profit x after discount y
model 2 hiking & discounting
model 3 successive discount
model 4 mixed discount problems of marked price
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