model 2 hiking & discounting Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 4 EXERCISES

Top 10,000+ Aptitude Memory Based Exercises

The following question based on discount topic of quantitative aptitude

Questions : A dealer marks his goods at 25% above the cost price and allows a discount of 10% for cash payment. His profit % is :

(a) 15%

(b) 20%

(c) 12.5%

(d) 17.5%

The correct answers to the above question in:

Answer: (c)

Let Cost price of article = Rs.100

Marked price = Rs.125

S.P. = ${125 × 90}/100$ = Rs.112.5

Gain = 112.5 - 100 = 12.5

Gain percent = 12.5%

Using Rule 8,

Here, r = 25%, $r_1$ = 10%

Profit % = ${r × (100 - r_1)}/100 - r_1$

= ${25 × (100 - 10)}/100 - 10$

= ${25 × 90}/100 - 10$

= 22.5 - 10 = 12.5%

Practice discount (model 2 hiking & discounting) Online Quiz

Discuss Form

Valid first name is required.
Please enter a valid email address.
Your genuine comment will be useful for all users! Each and every comment will be uploaded to the question after approval.

Read more based on hiking and discounting Based Quantitative Aptitude Questions and Answers

Question : 1

A tradesman marks his goods at 25% above its cost price and allows purchasers a discount of 12$1/2$% for cash payment. The profit, he thus makes, is

a) 9$1/2$%

b) 8$3/8$%

c) 8$1/2$%

d) 9$3/8$%

Answer: (d)

Let the cost price of article = Rs.100

Marked price = Rs.125

SP of the article

= $(100 - 25/2)$% of 125

= $175/2$% of 125

= ${125 × 175}/{2 × 100} = 875/8$

= Rs.109$3/8$

Gain percent

= $(109{3/8} -100) = 9{3}/8$%

Using Rule 8,

Here, r = 25%, $r_1 = 12{1}/2$% = 12.5%

Profit % = ${r × (100 - r_1)}/100 - r_1$

= ${25 × (100 - {12.5})}/100 - {12.5}$

= ${25 × 87.5}/100 - 12.5$

= 21.875 - 12.5

= 9.375 = 9$3/8$%

Question : 2

A shopkeeper marks his goods 20% above cost price, but allows 30% discount for cash. His net loss is :

a) 10%

b) 20%

c) 16%

d) 8%

Answer: (c)

Let the cost price be x

Mark Price

= $(1 + 20/100)x = 1.2x$

Cash price = $(1 - 30/100)1.2x$

= 0.7 × 1.2x = 0.84x

Net Loss = x - 0.84x = 0.16x

Net loss% = ${0.16x}/x × 100$ = 16%

Using Rule 8,

Here, r = 20%, $r_1$ = 30%

Profit or loss

= ${r × (100 - r_1)}/100 - r_1$

= ${20 × (100 - 30)}/100 - 30$

= 14 - 30 = –16% = 16% loss

Question : 3

Maha Bazaar offers 20% discount on bags which have been marked 50% above the cost price. Amarnath pays Rs.840 for a bag. Then the cost price of the bag is

a) Rs.700

b) Rs.810

c) Rs.790

d) Rs.672

Answer: (a)

Let the cost price be Rs.100.

Marked price = Rs.150

S.P. = ${150 × 80}/100$ = Rs.120

when S.P. = 120, C.P. = Rs.100

when S.P. = 840

C.P.= $100/120 × 840$ = Rs.700

Using Rule 8,

Here, r = 50%, $r_1$ = 20%, S.P. = Rs.840

Gain % = ${r × (100 - r_1)}/100 - r_1$

= ${50 × (100 - 20)}/100 - 20$

= ${50 × 80}/100 - 20$= 20%

We know that

Gain % = $\text"S.P. - C.P."/{C.P.} ×100$

20 = $({840 - x}/x) × 100$

20x= 84000 - 100x

120x = 84000

x = 700

∴ C.P. = Rs.700

Question : 4

To gain 8% after allowing a discount of 10%, by what per cent cost price should be hiked in the list price ?

a) 11%

b) 20%

c) 18%

d) 9%

Answer: (b)

Let the cost price be Rs.100

and marked price be x.

${x × 90}/100 = 108$

${9x}/10 = 108$

$x = {108 × 10}/9 = 120$

Required Percent = 20%

Using Rule 8,

Here, Gain % = 8%, $r_1$ = 10%, r = ?

Gain % = ${r × (100 - r_1)}/100 - r_1$

8 = ${r × (100 - 10)}/100 - 10$

8 = ${r × 90}/100 - 10$

8 = ${r × 9}/10$ = 20%

Question : 5

A merchant purchases a wrist watch for Rs.450 and fixes its list price in such a way that after allowing a discount of 10%, he earns a profit of 20%. Find the list price of the watch.

a) Rs.450

b) Rs.540

c) Rs.600

d) Rs.480

Answer: (c)

Let marked price of the wrist watch be x

${90x}/100 = {450 × 120}/100$

90x = 450 × 120

$x = {450 × 120}/90$ = Rs.600

Using Rule 8,

Here, $r_1$ = 10%, profit = 20%, r = ?

Gain % = ${r × (100 - r_1)}/100 - r_1$

20 = ${r × (100 - 10)}/100 - 10$

20 = ${9r}/10 - 10$

30 = ${9r}/10$

$r = 300/9$%

List price =450 + 450 × $300/9$%

= 450 + 450 × $300/900$

= 450 + 150 = Rs.600

Question : 6

A shopkeeper marks his goods at 30% above the cost price but allows a discount of 10% at the time of sale. His gain is

a) 20%

b) 17%

c) 18%

d) 21%

Answer: (b)

Let the CP of the article be 100.

According to the question,

The marked price = Rs.130

Discount = 10%

SP = 90% of 130

= ${130 × 90}/100$ = Rs.117

Gain = 117 - 100 = Rs.17

Gain per cent = 17%

since the CP = Rs.100

Using Rule 8,

Here, r = 30%, $r_1$ = 10%

gain % = ${r × (100 - r_1)}/100 - r_1$

= ${30 × (100 - 10)}/100 - 10$

= ${30 × 90}/100 - 10$ = 17%

Recently Added Subject & Categories For All Competitive Exams

100+ Quadratic Equation Questions Answers PDF for Bank

Quadratic Equation multiple choice questions with detailed answers for IBPS RRB SO. more than 250 Attitude practice test exercises for all competitive exams

03-Jul-2024 by Careericons

Continue Reading »

IBPS Aptitude Linear Equations MCQ Questions Answers PDF

Linear equations multiple choice questions with detailed answers for IBPS RRB SO. more than 250 Attitude practice test exercises for all competitive exams

03-Jul-2024 by Careericons

Continue Reading »

New 100+ Compound Interest MCQ with Answers PDF for IBPS

Compound Interest verbal ability questions and answers solutions with PDF for IBPS RRB PO. Aptitude Objective MCQ Practice Exercises all competitive exams

02-Jul-2024 by Careericons

Continue Reading »

100+ Mixture and Alligation MCQ Questions PDF for IBPS

Most importantly Mixture and Alligation multiple choice questions and answers with PDF for IBPS RRB PO. Aptitude MCQ Practice Exercises all Bank Exams

02-Jul-2024 by Careericons

Continue Reading »